2x - 11
-9 + x
equate the equations
2x - 11 = -9 + x
bring like terms to one side
2x - 11 = -9 + x
- x +11 +11 - x
-11 and +11 cancels out
+x and -x cancels out
2x - x = 11 - 9
x = 2
Answer:
Step-by-step explanation:
Brainly User
In my opinion, no. Others may think that when you subtract this way, it is much easier. My way to subtract numbers is below:-
Example: 17 - 11
Take the numbers that seem easy to add.
10 - 10 = 0
7 - 1 = 6
6+0 = 6
Now, we know that 17 - 11 = 6
We could have done it this way:-
17
- 11
----------
0 6
-kiara
Answer:
x = 13
Step-by-step explanation:

Take the square root of both sides

Answer:
The probability is 0.0052
Step-by-step explanation:
Let's call A the event that the four cards are aces, B the event that at least three are aces. So, the probability P(A/B) that all four are aces given that at least three are aces is calculated as:
P(A/B) = P(A∩B)/P(B)
The probability P(B) that at least three are aces is the sum of the following probabilities:
- The four card are aces: This is one hand from the 270,725 differents sets of four cards, so the probability is 1/270,725
- There are exactly 3 aces: we need to calculated how many hands have exactly 3 aces, so we are going to calculate de number of combinations or ways in which we can select k elements from a group of n elements. This can be calculated as:

So, the number of ways to select exactly 3 aces is:

Because we are going to select 3 aces from the 4 in the poker deck and we are going to select 1 card from the 48 that aren't aces. So the probability in this case is 192/270,725
Then, the probability P(B) that at least three are aces is:

On the other hand the probability P(A∩B) that the four cards are aces and at least three are aces is equal to the probability that the four card are aces, so:
P(A∩B) = 1/270,725
Finally, the probability P(A/B) that all four are aces given that at least three are aces is:
