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Luden [163]
3 years ago
14

The highest recorded temperature during the month of July for a given year in Death Valley, California has an approximately norm

al distribution with a mean of 123.8 degrees Fahrenheit and standard deviation of 3.1 deg. F (Weather Source, 2009). What is the probability for a given year that the temperature never exceeds 120 deg. F in a given July in Death Valley? Include leading zero, and state your answer to 3 decimal places.
Mathematics
1 answer:
S_A_V [24]3 years ago
6 0

Answer:

P(X

And we can find this probability using excel or the normal standard tabe and we got:

P(z

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the temperatures of a population, and for this case we know the distribution for X is given by:

X \sim N(123.8,3.1)  

Where \mu=123.8 and \sigma=3.1

We are interested on this probability

P(X

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X

And we can find this probability using excel or the normal standard tabe and we got:

P(z

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Solve for x , 2x-11 -9+ x
romanna [79]
2x - 11
-9 + x
equate the equations
2x - 11 = -9 + x
bring like terms to one side
2x - 11 = -9 + x
- x   +11   +11  - x
-11 and +11 cancels out
+x and -x cancels out
2x - x = 11 - 9
x = 2


3 0
3 years ago
Why is easier to subtract when numbers are written above and bellow each other?
attashe74 [19]

Answer:


Step-by-step explanation:

Brainly User

In my opinion, no. Others may think that when you subtract this way, it is much easier. My way to subtract numbers is below:-


Example: 17 - 11


Take the numbers that seem easy to add.


10 - 10 = 0

7 - 1 = 6

6+0 = 6


Now, we know that 17 - 11 = 6


We could have done it this way:-


  17

-  11

----------

 0 6

-kiara

5 0
3 years ago
Read 2 more answers
Who can help me out with this question???
GaryK [48]

Answer:

x = 13

Step-by-step explanation:

a^{2} +b^2 = c^2\\12^2 + 5^2 = c^2\\144 + 25 = c^2\\169 = c^2\\

Take the square root of both sides

\sqrt{169} = \sqrt{c^2} \\13 = c

8 0
3 years ago
Jeremy is $124.60 in debt to his grandparents. He determines that he can pay them back in five months. What effect will his repa
3241004551 [841]

Answer:

brainly.com/question/11536615

Step-by-step explanation:

8 0
3 years ago
Four cards are dealt from a standard fifty-two-card poker deck. What is the probability that all four are aces given that at lea
elena-s [515]

Answer:

The probability is 0.0052

Step-by-step explanation:

Let's call A the event that the four cards are aces, B the event that at least three are aces. So, the probability P(A/B) that all four are aces given that at least three are aces is calculated as:

P(A/B) =  P(A∩B)/P(B)

The probability P(B) that at least three are aces is the sum of the following probabilities:

  • The four card are aces: This is one hand from the 270,725 differents sets of four cards, so the probability is 1/270,725
  • There are exactly 3 aces: we need to calculated how many hands have exactly 3 aces, so we are going to calculate de number of combinations or ways in which we can select k elements from a group of n elements. This can be calculated as:

nCk=\frac{n!}{k!(n-k)!}

So, the number of ways to select exactly 3 aces is:

4C3*48C1=\frac{4!}{3!(4-3)!}*\frac{48!}{1!(48-1)!}=192

Because we are going to select 3 aces from the 4 in the poker deck and we are going to select 1 card from the 48 that aren't aces. So the probability in this case is 192/270,725

Then, the probability P(B) that at least three are aces is:

P(B)=\frac{1}{270,725} +\frac{192}{270,725} =\frac{193}{270,725}

On the other hand the probability P(A∩B) that the four cards are aces and at least three are aces is equal to the probability that the four card are aces, so:

P(A∩B) = 1/270,725

Finally, the probability P(A/B) that all four are aces given that at least three are aces is:

P=\frac{1/270,725}{193/270,725} =\frac{1}{193}=0.0052

5 0
3 years ago
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