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Juli2301 [7.4K]
3 years ago
8

Elena has 2 fewer hats then fran. Together, they have 14 hats. Which equation represents this situation.

Mathematics
1 answer:
Free_Kalibri [48]3 years ago
8 0
<h2>Greetings!</h2>

Answer:

2x - 2 = 14

Step-by-step explanation:

Let x be the amount of hats Fran has, if Elena has -2 hats, then this can be shown by x - 2

So then

x + x - 2 = 14

2x - 2 = 14

You haven't asked this but to find the amount of hats they have, move the -2 over to the other side making it a +2:

2x = 14 + 2

2x = 16

x = 8

So Fran has 8 hats and Elena has 6 hats.


<h2>Hope this helps!</h2>

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Step-by-step explanation:

x=children ticket

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3 children and 2 adult

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5x+9.00=81.50

5x+9.00-9.00=81.50-9.00

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The length of a rectangular prism is 8
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Surface area is:

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replacing the values

250=2*(8*W+8*1+W*1)

250=2*(8*W+8+W)

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\boxed{\boxed{W=13~unit~of~measure}}

The volume of a rectangular prism is

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garri49 [273]

Let W be the random variable representing the winnings you get for playing the game. Then

W=\begin{cases}10-1=9&\text{if the dice sum is odd}\\5-1=4&\text{if the dice sum is 4 or 8}\\50-1=49&\text{if the dice sum is 2 or 12}\\-1&\text{otherwise}\end{cases}

First thing to do is determine the probability of each of the above events. You roll two dice, which offers 6 * 6 = 36 possible outcomes. You find the probability of the above events by dividing the number of ways those events can occur by 36.

  • The sum is odd if one die is even and the other is odd. This can happen 2 * 3 * 3 = 18 ways. (3 ways to roll even with the first die, 3 ways to roll odd for the die, then multiply by 2 to count odd/even rolls)
  • The sum is 4 if you roll (1, 3), (2, 2), or (3, 1), and the sum is 8 if you roll (2, 6), (3, 5), (4, 4), (5, 3), or (6, 2). 8 ways.
  • The sum is 2 if you roll (1, 1), and the sum is 12 if you roll (6, 6). 2 ways.
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So the probability mass function for this game is

P(W=w)=\begin{cases}\frac12&\text{for }w=9\\\frac29&\text{for }w=4\text{ or }w=-1\\\frac1{18}&\text{for }w=49\\0&\text{otherwise}\end{cases}

The expected value of playing the game is then

E[W]=\displaystyle\sum_ww\,P(W=w)=\frac92+\frac89-\frac29+\frac{49}{18}=\frac{71}9

or about $7.89.

7 0
3 years ago
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