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Eduardwww [97]
3 years ago
7

On a coordinate plane, solid circles appear at the following points: (negative 3, 2), (negative 3, 3), (1, 4), (1, negative 4),

(2, negative 4), (2, negative 2).
How many points need to be removed from this graph so that it will be a function?

1 point
2 points
3 points
4 points
Mathematics
2 answers:
Mkey [24]3 years ago
5 0
4points I think ...............................
Natalija [7]3 years ago
3 0

Answer:

Wrong the answer is 3 points

Step-by-step explanation:

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Genrish500 [490]

Answer:

700

Step-by-step explanation:

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3 years ago
Evaluate 2(x + 1) - 3 when x = 6.<br> ОА. 5<br> ов. 8<br> Ос. 11<br> OD. 10
MrMuchimi

Answer:

plz mark brainliest.......

6 0
3 years ago
Given that sec (x) = 2 and cosec (x) is negative,
weeeeeb [17]

Answer:

i) sin(2x) = -\frac{\sqrt{3}}{2}

ii) cot(x+360) = -\frac{\sqrt{3}}{3}

iii) sin(x-180) = \frac{\sqrt{3}}{2}

Step-by-step explanation:

sec(x) = 2

Since cos(x) is reciprocal of sec(x), this means:

cos(x) = \frac{1}{2}

cosec(x) is negative , this means sin(x) is also negative. The only quadrant where cos(x), sec(x) are positive and sin(x), cosec(x) are negative is the 4th quadrant. Hence the terminal arm of the angle x is in 4th quadrant.

Part i)

sin(2x) can be simplified as:

sin(2x) = 2 sin(x) cos(x)

First we need to find the value of sin(x). According to Pythagorean identity:

sin^{2}(x)=1-cos^{2}(x)\\\\ sin(x)=\pm \sqrt{1-cos^{2}(x)}

Since, angle is in 4th quadrant, sin(x) will be negative. So considering the negative value of sin(x) and substituting the value of cos(x), we get:

sin(x)=- \sqrt{1-cos^{2}(x)}\\\\ sin(x)=-\sqrt{1-(\frac{1}{2})^{2}}\\\\ sin(x)=-\frac{\sqrt{3}}{2}

So,

sin(2x)=2 \times -\frac{\sqrt{3} }{2} \times \frac{1}{2}\\\\ sin(2x)=-\frac{\sqrt{3}}{2}

Part ii)

We have to find cot(x + 360)

An addition of 360 degrees to the angle brings it back to the same terminal point. So the trigonometric ratios of the original angle and new angle after adding 360 or any multiple of 360 stay the same. i.e.

cot(x + 360) = cot(x)

cot(x) = \frac{cos(x)}{sin(x)}\\

Using the values, we get:

cot(x)=\frac{\frac{1}{2}}{-\frac{\sqrt{3}}{2} }\\\\ cot(x)=-\frac{\sqrt{3}}{3}

Part iii)

We need to find the value of sin(x - 180)

sin(x - 180) = - sin(x)

Addition or subtraction of 180 degrees changes the angle by 2 quadrants. The sign of sin(x) becomes opposite if the angle jumps by 2 quadrants. For example, sin(x) is positive in 1st quadrant and negative in 3rd quadrant.

So,

sin(x - 180) = -(-\frac{\sqrt{3}}{2}) = \frac{\sqrt{3}}{2}

6 0
3 years ago
How to find the height of a triangle with only the sides?
UNO [17]
Use a square + b square = c square a and b are the short sides of a triangle and c is the largest side of a triangle.

5 0
3 years ago
If the translation is (x+1, y-4) and the image is (1,7), what is the preimage
EleoNora [17]

Answer:

The pre-image is the point (0,11)

Step-by-step explanation:

we know that

The rule of the translation is equal to

pre-mage------> image

(x,y) -----> (x+1,y-4)

so

we have that

(x+1,y-4)=(1,7)

so

x+1=1 -----> x=1-1=0

y-4=7 ----> y=7+4=11

therefore

The pre-image is the point (0,11)

4 0
3 years ago
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