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Nonamiya [84]
2 years ago
11

In one soccer season, a goalie saved 150 out of

Mathematics
1 answer:
Maru [420]2 years ago
7 0

Answer:

0.81 (rounded to the nearest hundredth) & 81%

Step-by-step explanation:

150/185 = 30/37 ≈ 0.81 (rounded to the nearest hundredth)

0.81 is 81%

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Michelle is fishing from a small boat. A fish swimming at the same depth as the hook at the end of her fishing line is 16 meters
Rama09 [41]

Answer:

12 meters

Step-by-step explanation:

You have to use the inverse of the pythagorean theorem to do this so you do square root of (20x20-16x16) which is 12

5 0
3 years ago
Find the length of AD in the diagram shown.
Sophie [7]
No diagram :(
can you upload a picture so we can help out or a description? thanks!
5 0
3 years ago
Find each percent increase round to the nearest percent from $5 to $8
asambeis [7]
First subtract the two numbers:

8 - 5 = 3

Now divide this to the original:

3 / 5 = 0.6

Multiply by 100:

0.6 * 100 = 60%
7 0
3 years ago
PLEASE HELP WILL MARK BRAINLIEST!!(plz show work too)
trapecia [35]

\huge \bf༆ Answer ༄

Let the capacity of bus be x students

And van be y students, now ;

From the given statements we get two equations ~

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:2x + 10y = 260 \:   \:  \:  \: \:  (1)

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:13x + 5y = 670 \:  \:  \:  \:  \: (2)

multiply the equation (2) with 2 [ it won't change the values ]

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:2x + 10y = 260 \: \:  \:  \:   \:  \:  \:  \:  \: (1)

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:26x + 10y = 1340 \:  \:  \:  \:  \: (3)

Now, deduct equation (1) from equation (3)

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:26x + 10y - 2x - 10y = 1340 - 260

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:24x = 1080

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:x = 1080 \div 24

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:x = 45

Therefore each bus can carry (x) = 45 students

Now, plug the value of x in equation (1) to find y ~

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:2x + 10y = 260

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:(2 \times 45) + 10y = 260

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:90 + 10y = 260

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:10y = 260 - 90

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:10y = 170

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:y = 170 \div 10

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:y = 17

Hence, each van can carry (y) = 17 students in total.

5 0
3 years ago
Find two number nearest to 8888888 which are exactly divisible by 2915​
Marysya12 [62]

Step-by-step explanation:

Given problem is to find nearest number,

= 8888888/2915

quotient = 3049

remainder= 1053

Now, 2915-1053 = 1862

8888888+1862 = 8890750

8888888-1053 = 8887835

Two numbers nearest to 8888888 which are exactly divisible by 2915 is 8887835 and 8890750

3 0
2 years ago
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