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jolli1 [7]
3 years ago
8

Is this right?? please help!

Mathematics
1 answer:
Ganezh [65]3 years ago
4 0

Answer:

  6 < x < 8

Step-by-step explanation:

The compound inequality in this instance represent the "and" condition, not the "or" condition.* We might solve it like this.

  -47 > 1 -8x > -63 . . . . given

Multiply by -1:

  47 < -1 +8x < 63

Add 1:

  48 < 8x < 64

Divide by 8:

  6 < x < 8

______

* You can tell this is the case by looking at the ends of the given statement:

  -47 > -63 . . . . a true statement, so the solution set will be an intersection, not a union.

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Step-by-step explanation:

The multiplier of her original salary to her reduced salary is ...

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The multiplier of her reduced salary after her raise is ...

  (1 +30%) = 1.30

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3 years ago
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The bike store marks up the wholesale cost of all of the bikes they sell by 30%.
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Answer:

A ) The money which Andre pay for the bike is $ 67.30

B ) The money which Andre pay for the bike is $ 76.92

Step-by-step explanation:

Given as :

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A ) The discount percentage = 30 %

Let The selling price of the bike after discount = s.p

Now ,

Discount % = \dfrac{m.p - s. p }{m . p}

or, 30 % = 1 - \dfrac{s. p }{m . p}

or, \dfrac{30 }{100} = 1 - \dfrac{s. p }{96.15}

Or, \dfrac{s. p }{96.15} = 1 -  \dfrac{30 }{100}

or,  \dfrac{s. p }{96.15} =  \dfrac{100 - 30 }{100}

Or,  \dfrac{s. p }{96.15} =  \dfrac{70}{100}

Or, s. p = \dfrac{70}{100} × 96.15

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So, He will pay $ 67.30

Hence The money which Andre pay for the bike is $ 67.30  . Answer

B ) If the bike is discounted by 20 % , let The selling price = s.p'

So,

Discount % = \dfrac{m.p - s. p }{m . p}

or, 20 % = 1 - \dfrac{s. p' }{m . p}

or, \dfrac{20 }{100} = 1 - \dfrac{s. p' }{96.15}

Or, \dfrac{s. p' }{96.15} = 1 -  \dfrac{20 }{100}

or,  \dfrac{s. p' }{96.15} =  \dfrac{100 - 20 }{100}

Or,  \dfrac{s. p' }{96.15} =  \dfrac{80}{100}

Or, s. p' = \dfrac{80}{100} × 96.15

∴  s.p' = $ 76.92

So, He will pay $ 76.92

Hence The money which Andre pay for the bike is $ 76.92  . Answer

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