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Serga [27]
4 years ago
11

Look at the parallelogram ABCD shown below: The table below shows the steps to prove that if the quadrilateral ABCD is a paralle

logram, then its opposite sides are congruent:
Statement Reasons 1 AB is parallel to DC and AD is parallel to BC Definition of parallelogram 2
angle 1 = angle 2, angle 3 = angle 4 If two parallel lines are cut by a transversal then the _______________ are congruent 3
BD = BD Reflexive Property 4
triangles ADB and CBD are congruent If two angles and the included side of a triangle are congruent to the corresponding angles and side of another triangle then the triangles are congruent by ASA postulate 5
AB = DC, AD = BC Corresponding parts of congruent triangles are congruent
Which choice completes the missing information for reason 2 in the chart?
alternate interior angles
corresponding angles
same-side interior angles
vertical angles

Mathematics
1 answer:
riadik2000 [5.3K]4 years ago
8 0

Answer:

The correct option is 1.

Step-by-step explanation:

Statement                                          Reasons

1.   AB is parallel to DC and         Definition of parallelogram

    AD is parallel to BC

2.   angle 1 = angle 2,                   If two parallel lines are cut by a

    angle 3 = angle 4                    transversal then the alternate

                                                      interior angles are congruent

3.    BD = BD                                   Reflexive Property

4.    \triangle ADB\cong \triangle CBD                 ASA postulate

5.   AB = DC, AD = BC                  (CPCTC)

If two angles and the included side of a triangle are congruent to the corresponding angles and side of another triangle then the triangles are congruent by ASA postulate.

According to alternate interior angles theorem, two parallel lines are cut by a transversal then the alternate interior angles are congruent.

Therefore option 1 is correct.

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Answer:

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Step-by-step explanation:

* Let us talk about the transformation

  • If the function f(x) reflected across the x-axis, then the new  function g(x) = - f(x)
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In the given question

∵ y = x² - 3

∵ The graph is translated 4 units to the left

→ That means substitute x by x + 4 as 4th rule above

∴ y = (x + 4)² - 3

→ Solve the bracket to put it in the form of y = ax² + bx + c

∵ (x + 4)² = (x + 4)(x + 4) = (x)(x) + (x)(4) + (4)(x) + (4)(4)

∴ (x + 4)² = x² + 4x + 4x + 16

→ Add the like terms

∴ (x + 4)² = x² + 8x + 16

→ Substitute it in the y above

∴ y = x² + 8x + 16 - 3

→ Add the like terms

∴ y = x² + 8x + 13

∴ b = 8 and c = 13

a) b = 8, c = 13

∵ The graph A is reflected in the x-axis

→ That means y will change to -y as 1st rule above

∴ -y = (x² - 3)

→ Multiply both sides by -1 to make y positive

∴ y = -(x² - 3)

→ Multiply the bracket by the negative sign

∴ y = -x² + 3

b) The equation of graph B is y = -x² + 3

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