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ruslelena [56]
3 years ago
10

Rogerio drives 1 hour and 18 min to meet a friend. the first 30 min of his trip was mostly highway driving, so he averaged 64 mi

les per hour for this portion. for the last 48 min of this trip, he averaged 50 miles per hour. what was his average speed for the entire trip?
A) 60 miles per hour
B) 58 miles per hour
C) 55 miles per hour
D) 53 miles per hour
Mathematics
2 answers:
Setler79 [48]3 years ago
7 0

Answer:

Step-by-step explanation:

d

math sucks

AlladinOne [14]3 years ago
7 0

Answer:

C) 55 miles per hour

Step-by-step explanation:

In order to calculate this you just have to see how many miles did he traveled and then divided that by the minutes that he spent.

So in the first part of the trip he traveled 30 minutes at a speed of 64 miles, that makes up for 32 miles.

And in the second part of the trip he traveled for 48 minutes at 50 miles per hour, that makes for 40 miles

So he traveled 72 miles total, divided by 78 minutes=.923 miles per minute, we just multiply this by 60 and we have that he traveled at 55.38 miles per hour.

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15% = \frac{15}{100} =  \frac{30}{100} which gives you the whole quality of the number of 200

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3 years ago
3x - 6y = 27<br><br> 3x + 4y = 17
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Answer: {x,y} = {27/4,-47/8}

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2 years ago
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Solve for h. -18+7h&gt;12+9h
Evgen [1.6K]

Answer:

h

Step-by-step explanation:

-18+7h>12+9h

Add 18 to both sides:

-18+7h+18>12+9h+18

7h>9h+30

Subtract 9h from both sides:

7h>9h+30

-2h>30

Multiply both sides by -1 and flip the symbol:

\left(-2h\right)\left(-1\right)

2h

Divide both sides by 2:

\frac{2h}{2}

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4 0
3 years ago
Scores on a university exam are Normally distributed with a mean of 78 and a standard deviation of 8. The professor teaching the
mafiozo [28]

Answer:

Porcentage of students score below 62 is close to 0,08%

Step-by-step explanation:

The rule

68-95-99.7

establishes:

The intervals:

[ μ₀ - 0,5σ ,  μ₀ + 0,5σ] contains 68.3 % of all the values of the population

[ μ₀ - σ ,  μ₀ + σ]   contains 95.4 % of all the values of the population

[ μ₀ - 1,5σ ,  μ₀ + 1,5σ] contains 99.7 % of all the values of the population

In our case such intervals become

[ μ₀ - 0,5σ ,  μ₀ + 0,5σ]   ⇒  [ 78 - (0,5)*8 , 78 + (0,5)*8 ]  ⇒[ 74 , 82]

[ μ₀ - σ ,  μ₀ + σ]  ⇒ [ 78 - 8 , 78 +8 ]   ⇒  [ 70 , 86 ]

[ μ₀ - 1,5σ ,  μ₀ + 1,5 σ]  ⇒ [ 78 - 12 , 78 + 12 ]  ⇒ [ 66 , 90 ]

Therefore the last interval

[ μ₀ - 1,5σ ,  μ₀ + 1,5 σ]    ⇒  [ 66 , 90 ]

has as lower limit 66 and contains 99.7 % of population, according to that the porcentage of students score below 62 is very small, minor than 0,15 %

100 - 99,7  = 0,3 %

Only 0,3 % of population is out of   μ₀ ± 1,5 σ, and by symmetry 0,3 /2 = 0,15 % is below the lower limit, 62 is even far from 66 so we can estimate, that the porcentage of students score below 62 is under 0,08 %

6 0
2 years ago
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