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3 years ago

10

How would I write a function rule f(x) = _x+_ If I have an x and y chart?

1 answer:

san4es73 [151]3 years ago

3 0

Y=ax+b. As simple as that!

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Help Please I'm Out Of Time ;(

trasher [3.6K]

Answer:

Total area = 31.5 unit²

Step-by-step explanation:

Assume 1 block = 1 unit²

Divide diagram into 3 part

1. 5 by 5 block square

2. 2 by 2 block triangle(1)

2. 3 by 3 block triangle(2)

Area of square = side × side

Area of square = 5 × 5

Area of square = 25 unit²

Area of triangle(1) = [1/2][base][height]

Area of triangle(1) = [1/2][2][2]

Area of triangle(1) = 2 unit²

Area of triangle(2) = [1/2][base][height]

Area of triangle(2) = [1/2][3][3]

Area of triangle(2) = 4.5 unit²

Total area = Area of square + Area of triangle(1) +Area of triangle(2)

Total area = 25 unit² + 2 unit² + 4.5 unit²

Total area = 31.5 unit²

6 0

3 years ago

Write an equation for line L in point-slope form and slope-intercept form.

Natalka [10]

Line L's slope intercept form is

y = 4x + 7

It's point slope form is

y - 3 = 4 (x - -1)

You can check the point slope form and match it with the slope intercept form:

y - 3 = 4 (x - -1)

y - 3 = 4x + 4

y = 4x + 7

y = 4x + 7 = y = 4x + 7

4 0

3 years ago

Read 2 more answers

Solve the systems using substitution.<br><br> − 2x − 5y = − 5<br> x = 5y − 20

Law Incorporation [45]

-2(5y-20) - 5y = -5
-10y + 40 - 5y = -5
-15y + 40 = -5
-15y = -45, y = 3
x = 5(3) - 20
x = 15 - 20, x = -5
Solution: x = -5, y = 3... or (-5,3)

7 0

3 years ago

A person on tour has dollar 360 for his daily expenses. If he extends his tour for 4 days, he has to cut down his daily expenses

mash [69]

Answer:

The original duration of the tour = 20 days

Step-by-step explanation:

Solution:

Total expenses for the tour = $360

Let the original tour duration be for $x$ days.

So, for $x$ days the total expense = $360

<em>Thus the daily expense in dollars can be given by</em> = $\frac{360}{x}$

Tour extension and effect on daily expenses.

The tour is extended by 4 days.

<em>Tour duration now</em> = $(x+4)$ days

On extension, his daily expense is cut by $3

<em>New daily expense in dollars </em>= $(\frac{360}{x}-3)$

Total expense in dollars can now be given as: $(x+4)(\frac{360}{x}-3)$

Simplifying by using distribution (FOIL).

$(x.\frac{360}{x})+(x(-3)+(4.\frac{360}{x})+(4(-3))$

$360-3x+\frac{1440}{x}-12$

$348-3x+\frac{1440}{x}$

We know total expense remains the same which is = $360.

So, we have the equation as:

$348-3x+\frac{1440}{x}=360$

Multiplying each term with $x$ to remove fractions.

$348x-3x^2+1440=360x$

Subtracting $348x$ both sides

$348x-348x-3x^2+1440=360x-348x$

$-3x^2+1440=12x$

Dividing each term with -3.

$\frac{-3x^2}{-3}+\frac{1440}{-3}=\frac{12x}{-3}$

$x^2-480=-4x$

Adding $4x$ both sides.

$x^2+4x-480=-4x+4x$

$x^2+4x-480=0$

Solving using quadratic formula.

For a quadratic equation: $ax^2+bx+c=0$

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

Plugging in values from the equation we got.

$x=\frac{-4\pm\sqrt{(4)^2-4(1)(-480)}}{2(1)}$

$x=\frac{-4\pm\sqrt{16+1920}}{2}$

$x=\frac{-4\pm\sqrt{1936}}{2}$

$x=\frac{-4\pm44}{2}$

So, we have

$x=\frac{-4+44}{2}$ and $x=\frac{-4-44}{2}$

$x=\frac{40}{2}$ and $x=\frac{-48}{2}$

∴ $x=20$ and $x=-24$

Since number of days cannot be negative, so we take $x=20$ as the solution for the equation.

Thus, the original duration of the tour = 20 days

6 0

3 years ago

The typical full-time employee in a particular hotel works a 40-hour week. Last month, the hotel's 80 employees worked a total o

Mila [183]

Answer: There are 25 FTEs.

Step-by-step explanation:

Since we have given that

Number of hour week for full time employee = 40 hours

In a month we know that

Number of weeks = 4

Total number of hours in a month would be

$40\times 4\\\\=160\ hours$

If in last month, the hotel's 80 employees worked a total of 4000 hours,

So, Full time equivalent workers were employed by the hotel last month would be

$\dfrac{4000}{160}\\\\=25$

Hence, there are 25 FTEs.

7 0

3 years ago