For Sodium would need to lose 11 electrons to become an ion.
Given:
mass of chlorine = 31.5 grams Cl2
temperature of water = 35 degrees C
volume of chlorine = 15 L
*water levels are equal
assume ideal gas behavior
Vapor pressure of water at 35 C = 42.2 torr
To solve for the barometric pressure, use the ideal gas equation:
PV = nRT
where P = Pgas - Pwater
(Pgas - 42.2 torr) * 15 L = 31.5g/70.9g/mol * (35 + 273) K * (760 torr * 22.4 L/298K)
solve for Pgas
Pgas = 563.36 torr
Therefore, the barometric pressure is 563.36 torr.
Hydrogen (in it's metal state), Lithium, Sodium, Potassium, Rubidium, Cesium, Francium, Beryllium, Magnesium, Calcium, Strontium, Barium, Radium, Aluminum, Gallium, Indium, Tin, Thallium, Lead Bismuth. Those are all I know but I'm pretty positive there are more.
Answer:
See explanation below
Explanation:
What we have to consider is the hybridation of the three carbon atoms we are asked in this question .
Hybridization # bonds Angle
sp³ 4 109.5º
sp² 3 + 1 pi bond 120º
sp 2 + 2 pi bonds 180º
Carbon atom (a) is bonded to two atoms: Carbon (b) and one Hydrogen. It has a triple bond to Carbon (b). Therefore its hybridization is sp with two pi bonds, and for sp hybridization we know the angle is 180 º.
The same hybridization sp happens to carbon (b) bonded to Carbon (c) and C(a) using one sp bond to Carbon (a) and 2 pi bonds; it is also bonded using the other sp to Carbon (c). The angle is therefore 180 between Carbons b and c.
Carbon C is bonded to 4 atoms, therefore, its hybridization is sp³ and the angles with these 4 atoms will be 109.5 º tehedral ( one bond to OH, one to C(b), and 2 to H ) .