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sergeinik [125]
3 years ago
8

Compound a, c8h10, undergoes nitration to give 2 products. The 1h nmr spectrum of a shows a complex five-proton multiplet at 7.2

7-7.40 δ, a two-proton quartet at 2.60 δ, and a three-proton triplet at 1.25 δ. What is the structure of a?

Chemistry
1 answer:
alekssr [168]3 years ago
8 0
<h3>Answer:</h3>

             Compound A is Ethylbenzene.

<h3>Explanation:</h3>

                   The structure of Ethylbenzene was elucidated and finalized based on following facts:

1)    The presence of multiplet signal ranging from δ  7.27 to 7.40 ppm confirms the presence of aromatic protons. Also the statement says that this signal is for 5 protons indicating that the benzene ring is mono substituted.

2)   The substituted group on benzene is Ethyl because the quartet for two protons shows that two protons (-CH₂-) are coupled with a CH₃ group. Hence, the ethyl group gives one quartet and one triplet signal.

3)    The chemical reaction stated in statement is Nitration reaction. Also, the alkyl group (ethyl) is ortho-para directing in nature. Hence, it will give two products i.e. 1-Ethyl-2-nitrobenzene and 1-Ethyl-4-nitrobenzene respectively.

Attached figure gives the calculated NMR spectrum of Ethylbenzene and the chemical shifts calculated are almost near to the given values. Also, the two products formed are shown.

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By formula; density= mass/volume; d=m/V

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2. NO (nitrogen monoxide) = 1*14 g/mol + 1*16 g/mol= 30 g/mol
3. NH₃ (ammonia)              = 1*14 g/mol + 3*1 g/mol= 17 g/mol
4. H₂O (water)                    = 2*1 g/mol + 1*16 g/mol= 18 g/mol
5. SO₂ (sulfur dioxide)        = 1*32 g/mol + 2*16 g/mol= 64 g/mol
Use Periodic Table to get atomic mass of elements.

Since their volumes are equal, compounds having the same molar mass will have the same density. 
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Ethane and nitrogen monoxide have the same density.

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