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ozzi
3 years ago
12

3x - y = 2 3x - y = 3

Mathematics
1 answer:
expeople1 [14]3 years ago
6 0

Answer:

there is no answer ( I mean this system of equations can't be solved)

Step-by-step explanation:

Because the x eliminates itself there will be no point.

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QveST [7]

Answer:

uyrhtdgfxgfgfxgfxfhxgfxhfchfchfcjy

5 0
2 years ago
What is <br>1.63 x 0.98 =​
yarga [219]

Answer:

1.5974

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Write and evaluate the expression. Then, complete the statements. A 1-column table with 5 rows. Column 1 is labeled Multiplicati
77julia77 [94]

Yuna ran three times as many kilometers so here expression should be 3k and the answer is 36.6

We have given that k = 12. 2

We have to find the expression

<h3>What is the writing and evaluating the expression?</h3>

Expressions are considered to be mathematical statements that have at least of two terms comprised of numbers or variables that should be linked. It could be of addition, subtraction, multiplication, or division.

Write the expression as  3k

Second, substitute 12.2 in for the variable, k.

Third,  simplify by  multiplying 3 and 12.2.

Therefore the answer is 36.6

Learn more about expression here:

brainly.com/question/723406

4 0
2 years ago
The number of typographical errors on a page of the first booklet is a Poisson random variable with mean 0.2. The number of typo
muminat

Answer:

The required probability is 0.55404.

Step-by-step explanation:

Consider the provided information.

The number of typographical errors on a page of the first booklet is a Poisson random variable with mean 0.2. The number of typographical errors on a page of second booklet is a Poisson random variable with mean 0.3.

Average error for 7 pages booklet and 5 pages booklet series is:

λ = 0.2×7 + 0.3×5 = 2.9

According to Poisson distribution: {\displaystyle P(k{\text{ events in interval}})={\frac {\lambda ^{k}e^{-\lambda }}{k!}}}

Where \lambda is average number of events.

The probability of more than 2 typographical errors in the two booklets in total is:

P(k > 2)= 1 - {P(k = 0) + P(k = 1) + P(k = 2)}

Substitute the respective values in the above formula.

P(k > 2)= 1 - ({\frac {2.9 ^{0}e^{-2.9}}{0!}} + \frac {2.9 ^{1}e^{-2.9}}{1!}} + \frac {2.9 ^{2}e^{-2.9}}{2!}})

P(k > 2)= 1 - (0.44596)

P(k > 2)=0.55404

Hence, the required probability is 0.55404.

4 0
3 years ago
I really need help with this algebra problem:<br> 5a=89
stiks02 [169]
Divide 5 by 89 and you get a=17.8
4 0
3 years ago
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