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3 years ago

6

if the bandwidth-delay product of a channel is 500 Mbps and 1 bit takes 25 milliseconds to make the roundtrip, what is the bandw

idth-delay product

Computers and Technology

1 answer:

Leona [35]3 years ago

8 0

Answer:

2500 kb

Explanation:

Here, we are to calculate the bandwidth delay product

From the question, we are given that

band width = 500 Mbps

The bandwidth-delay product is = 500 x 10^6 x 25 x 10^-3

= 2500 Kbits

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2) Please create a C program for the following: (25 points) a. Suppose the US dollar to Korean Won is 0.85 dollars to 1000 won.

Zanzabum

Answer:

In C:

#include <stdio.h>

int main(){

float won,usd,rupee,dinar,peso;

printf("Won: ");

scanf("%f", &won);

usd = won * 0.85/1000;

rupee = won * 0.85 * 0.14/1000;

dinar = won * 0.85 * 0.048/1000;

peso = won * 0.85 * 1.41/1000;

printf("USD = %f\n", usd);

printf("Rupee = %f\n", rupee);

printf("Dinar = %f\n", dinar);

printf("Peso = %f\n", peso);

return 0;

}

Explanation:

This declares all variables as float

float won,usd,rupee,dinar,peso;

This prompts the user for Korean Won

printf("Won: ");

This gets the input for won

scanf("%f", &won);

This converts to usd

usd = won * 0.85/1000;

This converts to rupee

rupee = won * 0.85 * 0.14/1000;

This converts to dinar

dinar = won * 0.85 * 0.048/1000;

This converts to peso

peso = won * 0.85 * 1.41/1000;

The next four lines print the converted currencies

printf("USD = %f\n", usd);

printf("Rupee = %f\n", rupee);

printf("Dinar = %f\n", dinar);

printf("Peso = %f\n", peso);

3 0

3 years ago

Write a program that reads an unspecified number of integers, determines how many positive and negative values have been read, a

GarryVolchara [31]

Answer:

<em>C++</em>

////////////////////////////////////////////////////////////////////////////////////////////////////////

#include <iostream>

#include <vector>

using namespace std;

int main() {

vector<int> v;

int n = 1;

while (n != 0) {

cout<<"Enter an integer, the input ends if it is 0: ";

cin>>n;

v.push_back(n);

}

cout<<endl;

///////////////////////////////////////////////////////////

int sum = 0;

int num_positives = 0, num_negatives = 0;

for (int i=0; i<v.size()-1; i++) {

if (v[i] > 0)

++num_positives;

else

++num_negatives;

sum = sum + v[i];

}

//////////////////////////////////////////////////////////

cout<<"The number of positives is "<<num_positives<<endl;

cout<<"The number of negatives is "<<num_negatives<<endl;

cout<<"The total is "<<sum<<endl;

cout<<"The average is "<<(float)sum/(v.size()-1);

///////////////////////////////////////////////////////////

return 0;

}

5 0

3 years ago

Who where the romanovs? What happened to them ?

Vikentia [17]

They where high ranking aristocrats in Russia during the 16th century. They where all executed.

5 0

3 years ago

Which emerging technologies will have more injury on our day to day country & How?

qwelly [4]

Explanation:

Complete the sentence with the words below stop push direction slow down move shape speed up pull A force is a. or a.

4 0

2 years ago

Primary U.S. interstate highways are numbered 1-99. Odd numbers (like the 5 or 95) go north/south, and events (like the 10 or 90

Norma-Jean [14]

Answer:

The C code for the problem is given below

Explanation:

#include <stdio.h>

int main() {

int highwayNumber;

int primaryNumber;

scanf("%d", &highwayNumber);

if (highwayNumber >= 1 && highwayNumber <= 999) {

if (highwayNumber <= 99) {

if (highwayNumber % 2 == 0) {

printf("I-%d is primary, going east/west.\n", highwayNumber);

} else {

printf("I-%d is primary, going north/south.\n", highwayNumber);

}

} else {

primaryNumber = highwayNumber;

highwayNumber %= 100;

if (highwayNumber % 2 == 0) {

printf("I-%d is auxiliary, serving the I-%d, going east/west.\n", primaryNumber, highwayNumber);

} else {

printf("I-%d is auxiliary, serving the I-%d, going north/south.\n", primaryNumber, highwayNumber);

}

}

} else {

printf("%d is not a valid interstate highway number.\n", highwayNumber);

}

return 0;

}

4 0

3 years ago

Read 2 more answers