The slope of the line between two points is known as the rate of change in the relation.

FIRST PERSON TO ANSWER GETS BRAINLIEST OR FIVE STARS Define the domain and range of the function.

uysha [10]

Answer:

Domain: (-∞, ∞)

Range: (-∞, ∞)

Step-by-step explanation:

The domain are the x-values included in the function (the horizontal axis).

The range are the y-values included in the function (the vertical axis).

The two arrows on the ends of the line (pointing upwards and downwards respectively) indicate that the function goes in those direction for infinity. Therefore, if there are an infinite amount of y-values, the range is (-∞, ∞).

While the slope is quite steep, there is still a slope and slowly "expands" the line on the horizontal axis. Because there is no limit to the y-values, the domain will also expand infinitely. Therefore, the domain is also (-∞, ∞).

7 0

2 years ago

Read 2 more answers

Given r(x) = startfraction 11 over (x minus 4) squared endfraction , which represents a domain restriction on r(x) and the corre

Dmitry_Shevchenko [17]

The domain and inverse of the function

$r(x) = \frac{11}{(x - 4)^2}$ is

Domain = $\mathbb{R} - \{4\}$ ,

$r^{-1}(x) = \pm \sqrt{\frac{11}{x}} + 4$

What is a function?

A function from A to B is a rule that assigns to each element of A a unique element of B. A is called the domain of the function and B is called the codomain of the function.

There are different operations on functions like addition, subtraction, multiplication, division and composition of functions.

The given function is

$r(x) = \frac{11}{(x - 4)^2}$

r(x) is not defined if x - 4 = 0

r(x) is not defined for x = 4

Domain = $\mathbb{R} - \{4\}$ ,

Where $\mathbb{R}$ is the set of all real number

Let r(x) = y

$\frac{11}{(x-4)^2} = y\\(x - 4)^2 = \frac{11}{y}\\x - 4 = \pm \sqrt{\frac{11}{y}}\\x = \pm\sqrt{\frac{11}{y}} +4$

<em /> $r^{-1}(x) = \pm \sqrt{\frac{11}{x}} + 4$

To learn more about function, refer to the link:

brainly.com/question/22340031

#SPJ4

3 0

1 year ago

there are five bells which ring at interval of 4,5,12 and 15 minutes respectively at what minute those bells ring at the same ti

Rus_ich [418]

<h3>Answer: 60 minutes</h3>

=====================================================

Explanation:

Let's find the LCM of 4 and 5, which are the first two items of the list.

multiples of 4 are: 4,8,12,16,20,24,...
multiples of 5 are: 5,10,15,20,25,...

The smallest item in each list is 20, so the LCM of 4 and 5 is 20.

We can replace the "4,5" in the list "4,5,12,15" with "20". So our new list would be "20,12,15".

We then repeat the process of finding the LCM of the first two items

multiples of 20 are: 20,40,60,80,...
multiples of 12 are: 12,24,36,48,60,72,...

LCM of 20 and 12 is 60.

The list "20,12,15" condenses to "60,15".

Repeat this process of finding the LCM once more and you'll find the overall LCM is 60.

Therefore, the LCM of the entire set {4,5,12,15} is 60. This is the smallest multiple shared by all four values. Interestingly enough, the outer values pair up to multiply to 60, and so do the inner values.

4*15 = 60

5*12 = 60

The bells ring together every <u>60 minutes</u>

In other words, all of the bells ring together at the same time every hour (perhaps at the top of every hour; eg at 7:00 pm and at 8:00 pm, etc).

8 0

2 years ago

Simply the expression 6-2X+5+4x

Lerok [7]

Answer:

2x + 11

I hope this helps!

4 0

3 years ago

Read 2 more answers

I need help with this

kotegsom [21]

Answer:

Here is the summary of true statements:

A) The statement of the function modeled is (0, 3) is TRUE.

D) the equation for the line function is y = 2x+3 is TRUE.

E) the given table represents the linear function is TRUE

Step-by-step explanation:

Given the table

x 1 3 5 7

y 5 9 13 17

E)

It is clear that there is a CONSTANT CHANGE in the x and y values of the graph.

THE CONSTANT CHANGE IN X VALUES

i.e. 3-1=2, 5-3=2, 7-5=2

THE CONSTANT CHANGE IN Y VALUES

i.e. 9-5 = 4, 13 - 9 = 4, 17 - 13 = 4

Thus, the given table represents the linear function is TRUE

B)

It is clear that the value of y increase as the value of x increases.

Thus, the statement ''the value of y decreases as the value of x increases'' is FALSE!

D)

We know that the slop-intercept form of the line equation is

$y = mx+b$

where m is the slope and b is the y-intercept.

Determining the equation

Taking two points

(1, 5)

(3, 9)

Finding the slope between (1, 5) and (3, 9)

Using the formula

Slope = m = [y₂ - y₁] / [x₂ - x₁]

= [9 - 5] / [3 - 1]

= 4 / 2

= 2

Thus, the slope of the line = m = 2

now substituting m = 2 and the point (1, 5) to determine the y-intercept

y = mx+b

5 = 2(1) + b

b = 5-2

b = 3

Thus, the value of y-intercept b = 3

substituting b = 3 and m = 2 in the slope-intercept form

y = mx+b

y = 2x+3

Therefore, the equation for the line function is y = 2x+3 is TRUE

A)

We know that the value of the y-intercept can be determined by setting x = 0, and determining the corresponding value of y.

We already know that the y-intercept b = 3

It means the y-intercept modeled is (0, 3)

Therefore, the statement of the function modeled is (0, 3) is TRUE.

C)

We have already got the equation

y = 2x+3

substituting x = 8

y = 2(8)+3

y = 10+3

y = 13

so at x = 8, the value of y = 13

Therefore, the statement that the ''On a graph of the function when x = 8, the value of y will be 2'' is FALSE!

Conclusion:

Here is the summary of true statements:

A) The statement of the function modeled is (0, 3) is TRUE.

D) the equation for the line function is y = 2x+3 is TRUE.

E) the given table represents the linear function is TRUE

3 0

3 years ago