3 years ago

Find the distance from (-6, 1) to (-3, 5).

Mathematics

1 answer:

MrRissso [65]3 years ago

5 0

Answer:

9.8 units

Step-by-step explanation:

distance = sqrt (x2 - x1)^2 + ( y2 - y1)^2

sqrt (-3 - (-6))^2 + (5 - 1)^2

sqrt (9)^2 + (4)^2

sqrt 81 + 16

sqrt 97

9.848857802

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Anon25 [30]

80 because tens place is two over from the right

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3 years ago

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6c + 7c +7c + 8c + 9c nesesito de su ayuda plis

Zielflug [23.3K]

Answer:

37c

Step-by-step explanation:

6c+(7c+7c)+8c+9c

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3 years ago

Find the length of diagonal HJ. Round to the nearest hundredth.

Alisiya [41]

Answer:

The length of the diagonal HJ is 10.82 units

Step-by-step explanation:

* Lets revise the rule of the distance between two points

- $d=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$ , where

$(x_{1},y_{1})$ and $(x_{2},y_{2})$ are the two points

* Lets use this rule to find the length of the diagonal HJ

∵ The coordinates of point H are (-4 , 3)

∵ The coordinates of point J are (5 , -3)

∴ $x_{1}=-4$ and $x_{2}=5$

∴ $y_{1}=3$ and $y_{2}=-3$

- Lets find the length of the diagonal HJ by using the rule above

∴ HJ = $\sqrt{(5-(-4))^{2}+(-3-3)^{2}}=\sqrt{(5+4)^{2}+(-6)^{2}}$

∴ HJ = $\sqrt{(9)^{2}+36}=\sqrt{81+36}=\sqrt{117}=10.81665$

∴ HJ = 10.82

* The length of the diagonal HJ is 10.82 units

7 0

3 years ago

Please help me with this problem and if you can show your work

ella [17]

Answer:

2.9

just answering wrong because i need points sorry

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2 years ago

What is (2,8) m=3 in slope intercept form

nignag [31]

Answer: y=3x+2

Step-by-step explanation:

y=mx+b

Plug in point (x,y)-->(6,8) m=3

8=3 (6) +b

2=b

5 0

3 years ago