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larisa86 [58]
3 years ago
11

What is the answer for this question?

Mathematics
1 answer:
drek231 [11]3 years ago
8 0

Answer: B

Step-by-step explanation:

(-3, -1) and (4, 5) are the points given

Slope formula: \frac{Y2-Y1}{X2-X1}

\frac{5--1}{4--3} = \frac{5+1}{4+3} \\

\frac{5+1}{4+3} = \frac{6}{7}

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NISA [10]

Answer:

The minimum value of this quadratic function is -4.

At the point (-4, 0), the x-axis intercepts with the quadratic graph.

There is 1 root of this quadratic equation.

Approximately, when y=1, the x value could be -5 or -3.

7 0
3 years ago
1.10 x 2^3 + 7^2 - 9 + 8<br> 2. 2 x [13+5 -14 ÷(3+4)}<br> 3. 39 ÷ (2+1) - 2 x(4+1)
Alisiya [41]

Answer:

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3 years ago
X^2+10x+16=0 how to slove this question?
Ksju [112]
You can factor this
x^2 + 10x  + 16 = 0

(x + 8)(x + 2) = 0

so x + 8 =0  or x + 2 = 0 

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8 0
3 years ago
Mason loves collecting sea glass from the beach. He recorded the weight of each jar full of sea glass. If he decided to distribu
lara31 [8.8K]

<em>The missing weights are:</em>

<em>2 2 2 1 11 12 12 2 24 22 24 3 37 22</em>

Answer:

Average = 12\frac{4}{7} \ lb

Step-by-step explanation:

Given

Weight of sea glass

To solve this question, we have to calculate the mean of the weight of the sea glass as follows;

Average = \frac{\sum x}{n}

Where n = number of sea glass

n = 14

So:

Average = \frac{\sum x}{n} becomes

Average = \frac{2 +2 + 2 + 1 + 11 +12 +12 +2 +24+22 +24 +3 +37+ 22}{14}

Average = \frac{176}{14}

Average = 12\frac{8}{14}

Simplify fraction

Average = 12\frac{4}{7}

<em>Hence; the weight of the sea glass would be </em>12\frac{4}{7}\ lb<em> </em><em>when evenly distributed...</em>

4 0
3 years ago
A constant force of 15 N is being applied at a constant angle os 30 degree on an object at the same time that a constant force o
Setler [38]

Step-by-step explanation:

Solution:

(a) is the vertical direction, the force of gravity

on the object (or the wight force: w = Mg ) pulls the crate down while the surface reaction. N. pushes it 103N

rd, as shown:

w = Mg = (20.0kg 9.8m s3 - 196N

N- 196N as well

(b) In the horizontal direction, in the absence of

friction, there are two forces: (F) and the 53-N force. Applying the Newton's 2nd law helps the calculation of the unknown force. F. F - 53N (20.0 kg)(2.5 m 3

F = 103N plz mark me as brainliest

6 0
3 years ago
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