The handshake problem!
Each of the five will play against 4 others, but since A vs B can be considered the same game as B vs A, so there are 5*4/2=10 matches.
Answer
584.56714755 = 146
Step-by-step explanation:
584.567 is 4 times 146 ...
...and 4 can be written as 2 to the power 2.
So, the 4 can just be pulled outside of the radical sign, as a 2 ,
and the other factor, the 146 , just stays inside of the radical sign.
Answer:
Commutative property
Step-by-step explanation:
Hope that helps!
Answer:
ohh try the tutor well help you with this
A <em>number line</em> is a <u>system</u> that shows the location of all <em>directed numbers </em>on a <u>straight</u> <u>line</u>. All <em>numbers</em> can be plotted on a <em>number line</em>. Thus the required answer to the given question is; Option A. Point A is <em>twenty-two</em> <em>ninths</em>, point B is <em>square root</em> of 10, and point C is <em>square root</em> of 13.
A <u>line</u> on which the <em>locations</em> of all <em>directed number</em>s can be shown is termed a <u>number line</u>. It has <u>two</u> extreme ends ranging from -∞ to +∞. Note that all <em>numbers</em> can be plotted on a <em>number line</em>. So that the <u>position</u> of any given <em>number</em> can be shown on the <u>line</u>.
In the given question, we have:
i. square root of 10 = 
= 3.2
ii. square root of 13 = 
= 3.6
iii. twenty-two ninths = 
= 2.4
But it has been given that;
Number line with points plotted at; <em>two</em> and <em>four-tenths</em> labeled point<u> A,</u> <em>three</em> and <em>two-tenths</em> labeled point <u>B</u>, and <em>three</em> and <em>six-tenths</em> labeled Point <u>C.</u>
Therefore,
Point A is <em>twenty-two ninths</em>, point B is <u>square</u> <u>root </u>of 10, and point C is <em>square root</em> of 13.
Thus the correct <u>option</u> is A.
For more clarifications on number line visit: brainly.com/question/22567573
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