The answer to this problem would be 12. If you need to show work just comment.
Answer:
6
Step-by-step explanation:
Size times flavor. 3 times 2 = 6
The equation of a hyperbola is
/9 -
/4 = 1
What are the steps to Hyperbola equation ?
To find the equation of hyperbola, the following steps must be taken. You need to identify;
- The coordinate of the center
- The coordinate of the vertices
- The coordinate of the foci
The general equation of a hyperbola can be expressed as
/
-
/
= 1
From the graph, we have the following parameters
a = 3
=
= 9
b = 2
=
= 4
The equation of a hyperbola can be expressed as
/9 -
/4 = 1
The vertices = V(+/-a,0) = (+/-3,0)
The center = C(0,0)
The focus = F(+/-C, 0)
Where
=
+ 
C = 
C = 
Focus = F(+/-
, 0)
The general equation for asymptote = +/- b/a X
= +/-2/3X
Therefore, the equation of a hyperbola can be expressed as
/9 -
/4 = 1
Learn more about hyperbola here: brainly.com/question/3405939
#SPJ1
to find the distance between 2 points we should apply the formula
![d=\sqrt[]{(x_2-x_1)^2+(y_2-_{}y_1)^2_{}}](https://tex.z-dn.net/?f=d%3D%5Csqrt%5B%5D%7B%28x_2-x_1%29%5E2%2B%28y_2-_%7B%7Dy_1%29%5E2_%7B%7D%7D)
call point q as point 1 for reference in the formula and p as point 2
replace the coordinates in the formula
![d=\sqrt[]{(3-(-1))^2+(-4-(-1))^2}](https://tex.z-dn.net/?f=d%3D%5Csqrt%5B%5D%7B%283-%28-1%29%29%5E2%2B%28-4-%28-1%29%29%5E2%7D)
simplify the equation
![\begin{gathered} d=\sqrt[]{(3+1)^2+(-4+1)^2} \\ d=\sqrt[]{4^2+(-3)^2} \\ d=\sqrt[]{16+9} \\ d=\sqrt[]{25} \\ d=5 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20d%3D%5Csqrt%5B%5D%7B%283%2B1%29%5E2%2B%28-4%2B1%29%5E2%7D%20%5C%5C%20d%3D%5Csqrt%5B%5D%7B4%5E2%2B%28-3%29%5E2%7D%20%5C%5C%20d%3D%5Csqrt%5B%5D%7B16%2B9%7D%20%5C%5C%20d%3D%5Csqrt%5B%5D%7B25%7D%20%5C%5C%20d%3D5%20%5Cend%7Bgathered%7D)
the distance between the 2 points is 5 units
Answer:

Step-by-step explanation:
Hi there!
<u>What we need to know:</u>
- Linear equations are typically organized in slope-intercept form:
where m is the slope and b is the y-intercept (the value of y when x is 0) - Perpendicular lines always have slopes that are negative reciprocals (ex. 3 and -1/3, 5/6 and -6/5, etc.)
<u>1) Determine the slope (m)</u>
y=x-9
Rewrite the equation
y=1x-9
Now, we can identify clearly that the slope of the line is 1. The negative reciprocal of 1 is -1, so therefore, the slope of a perpendicular line would be -1. Plug this into
:

<u />
<u>2) Determine the y-intercept (b)</u>

Plug in the given point (7,9) and solve for b

Add 7 to both sides to isolate b

Therefore, the y-intercept is 16. Plug this back into
:

I hope this helps!