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dimulka [17.4K]
3 years ago
15

Item 5

Mathematics
1 answer:
Sedbober [7]3 years ago
3 0

Answer: 300.3858/ maybe 300.385

Step-by-step explanation: 4 2/7 as decimal= 4.29 x (-18) = -77.22 x -3.89=  300.3858 (3.89 = decimal form of -3 8/9)  300.3858 x 1 = 300.3858

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Mashcka [7]

The answer to this problem would be 12. If you need to show work just comment.

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So, you go to a Coffee Shop. They have either small, medium or large coffee. They have vanilla or hazelnut flavor. What are the
Talja [164]

Answer:

6

Step-by-step explanation:

Size times flavor. 3 times 2 = 6

6 0
3 years ago
Will give brainliest
pychu [463]

The equation of a hyperbola is  x^{2}/9 - y^{2}/4 = 1

What are the steps to Hyperbola equation ?

To find the equation of hyperbola, the following steps must be taken. You need to identify;

  • The coordinate of the center
  • The coordinate of the vertices
  • The coordinate of the foci

The general equation of a hyperbola can be expressed as

x^{2}/a^{2} - y^{2}/b^{2} = 1

From the graph, we have the following parameters

a = 3

a^{2} = 3^{2} = 9

b = 2

b^{2} = 2^{2} = 4

The equation of a hyperbola can be expressed as

x^{2}/9 - y^{2}/4 = 1

The vertices = V(+/-a,0) = (+/-3,0)

The center = C(0,0)

The focus = F(+/-C, 0)

Where C^{2} = a^{2}  + b^{2}

C = \sqrt{9 + 4}

C = \sqrt{13}

Focus = F(+/- \sqrt{13}, 0)

The general equation for asymptote = +/- b/a X

= +/-2/3X

Therefore, the equation of a hyperbola can be expressed as

x^{2}/9 - y^{2}/4 = 1

Learn more about hyperbola here: brainly.com/question/3405939

#SPJ1

6 0
2 years ago
What is the distance from P to Q ?A. 7 unitsB. 5 unitsC. 1 unitD. 25 unitshow do I find the distance from P to Q?
Alex17521 [72]

to find the distance between 2 points we should apply the formula

d=\sqrt[]{(x_2-x_1)^2+(y_2-_{}y_1)^2_{}}

call point q as point 1 for reference in the formula and p as point 2

replace the coordinates in the formula

d=\sqrt[]{(3-(-1))^2+(-4-(-1))^2}

simplify the equation

\begin{gathered} d=\sqrt[]{(3+1)^2+(-4+1)^2} \\ d=\sqrt[]{4^2+(-3)^2} \\ d=\sqrt[]{16+9} \\ d=\sqrt[]{25} \\ d=5 \end{gathered}

the distance between the 2 points is 5 units

7 0
1 year ago
Find the equation of the line that is perpendicular to the line
ddd [48]

Answer:

y=-x+16

Step-by-step explanation:

Hi there!

<u>What we need to know:</u>

  • Linear equations are typically organized in slope-intercept form: y=mx+b where m is the slope and b is the y-intercept (the value of y when x is 0)
  • Perpendicular lines always have slopes that are negative reciprocals (ex. 3 and -1/3, 5/6 and -6/5, etc.)

<u>1) Determine the slope (m)</u>

y=x-9

Rewrite the equation

y=1x-9

Now, we can identify clearly that the slope of the line is 1. The negative reciprocal of 1 is -1, so therefore, the slope of a perpendicular line would be -1. Plug this into y=mx+b:

y=-1x+b\\y=-x+b

<u />

<u>2) Determine the y-intercept (b)</u>

y=-x+b

Plug in the given point (7,9) and solve for b

9=-7+b

Add 7 to both sides to isolate b

9+7=-7+b+7\\16=b

Therefore, the y-intercept is 16. Plug this back into y=-x+b:

y=-x+16

I hope this helps!

6 0
3 years ago
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