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koban [17]
3 years ago
6

The width of a rectangle is 5 meters less than its​ length, and the perimeter is 34 meters. Find the length and width of the rec

tangle.
Mathematics
1 answer:
Alona [7]3 years ago
3 0

Answer:

Length = 11

Width = 6

Step-by-step explanation:

We know that the length is x and the width is x - 5 since it is 5 less than the length.

The equation to find the perimeter of a rectangle is 2w + 2l

We will plug in the values and solve

2(x-5) + 2(x) = 34

2x - 10 + 2x = 34

4x - 10 = 34

4x = 44

x = 11

Since the length is simply x, we know that it is 11. We subtract 5 to find the width.

11 - 5 = 6.

The width is 6.

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Answer:

It's 3

Step-by-step explanation:

if you go to desmos graphing calculator it'll help you get the solutions for these if you type it in every number and letter and for exponents type ^ its shift then type 6.

8 0
2 years ago
Laura has a backyard that she wants to renovate. Her
miskamm [114]

Answer:

Area of the walkway = 8<em>x </em>+ 24

Step-by-step explanation:

Area of the total backyard = l\times b

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Now, Area of the rectangular garden = l\times b

Area of the rectangular garden = x (x+2) = x^{2} + 2x

Now area of the walkway poured with concrete = Area of the backyard - Area of the rectangular garden

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= x^{2} + 10x +24 - x^{2} -2x

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3 years ago
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Step-by-step explanation:

5 0
2 years ago
Express the system as AX = B; then solve using matrix inverses
Wittaler [7]

Answer with explanation:

1. The given equations are

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-x+2 y= 0

⇒The matrix in the form of , AX=B, is

A=\left[\begin{array}{cc}3&-5\\-1&2\end{array}\right] ,\\\\ X=\left[\begin{array}{c}x&y\end{array}\right],\\\\B=\left[\begin{array}{c}2&0\end{array}\right]

\rightarrow X=A^{-1}B\\\\\rightarrow X=\frac{Adj.A}{|A|}\times B

Adj.A=Transpose of cofactor of Matrix A

Adj.A=\left[\begin{array}{cc}2&1\\5&3\end{array}\right] ,\\\\ |A|=6-5\\\\|A|=1\\\\\left[\begin{array}{c}x&y\end{array}\right]=\left[\begin{array}{cc}2&5\\1&3\end{array}\right] \times \left[\begin{array}{c}2&0\end{array}\right]\\\\x=4, y=2

2.

The given equations are

x+y-z=2

x+z=7

2 x +y+z=13

⇒The matrix in the form of , AX=B, is

   A=\left[\begin{array}{ccc}1&1&-1\\1&0&1\\2&1&1\end{array}\right]\\\\ X=\left[\begin{array}{ccc}x\\y\\z\end{array}\right]\\\\B= \left[\begin{array}{ccc}2\\7\\13\end{array}\right]\\\\\rightarrow X=A^{-1}B\\\\\rightarrow X=\frac{Adj.A}{|A|}\times B\\\\a_{11}=-1,a_{12}=1,a_{13}=1,a_{21}=-2,a_{22}=3,a_{23}=1,a_{31}=1,a_{32}=-2,a_{33}=-1\\\\|A|=1\times(0-1)-1\times(1-2)-1\times(1-0)\\\\=-1+1-1\\\\|A|=-1\\\\Adj.A=\left[\begin{array}{ccc}-1&-2&1\\1&3&-2\\1&1&-1\end{array}\right]

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3 years ago
Which statement holds true for a skewed histogram showing a distribution of the weights of students in a class?
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Among the choices, the statement which describes a skewed histogram showing a distribution of the weights of students in a class is:

<span>"The nature of the skew can be verified by the position of the mean with respect to the mode."

The histogram is skewed to the right if the mean is less than the mode and the histogram is skewed to the left if the mean is more than the mode. </span><span />
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