<span>Problem 1: 2x > 4x - 6
2x < 6
x < 3
problem 2: -3r < 10 - r
-2r < 10
r > -5
problem 3: 5c - 4 > 8c + 2
3c < -6
c < -2</span>
Answer:
The value of k is -11
Step-by-step explanation:
If (x+2) is a factor of x3 − 6x2 + kx + 10:
Then,
f(x)=x3 − 6x2 + kx + 10
f(-2)=0
f(-2)=(-2)³-6(-2)²+k(-2)+10=0
f(-2)= -8-6(4)-2k+10=0
f(-2)= -8-24-2k+10=0
Solve the like terms:
f(-2)=-2k-22=0
f(-2)=-2k=0+22
-2k=22
k=22/-2
k=-11
Hence the value of k is -11....
We can check this by seeing if Pythagorean's theorem applies. The longest side is the hypotenuse, so let's see if this is true:
This is, indeed correct, thus, this
<em>is </em><em>
a right triangle.</em>
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