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creativ13 [48]
3 years ago
10

Please helppp!!!!

Mathematics
1 answer:
Nostrana [21]3 years ago
8 0

Answer:

ok more info please and I can help

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NEED HELP Fast open up the Screenshot
Evgesh-ka [11]
I think the answer is A but I am not sure. I think you would take the opposite of the y axis.
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3 years ago
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A triangle has side lengths measuring 2x + 2 ft, x + 3 ft, and n ft.
brilliants [131]

Answer:

The correct option is A. x – 1 < n < 3x + 5

Step-by-step explanation:

In a triangle sum of any two sides is always greater than the third side.

Now, the sides of the triangle are given to be :

2x + 2, x + 3 , n

Now, first take 2x + 2 and x + 3 as two sides and the side of length n as third side.

By using the property that sum of two sides is always greater than the third side in a triangle.

⇒ 2x + 2 + x + 3 > n

⇒ 3x + 5 > n  ......(1)

Now, take n and x + 3 as two sides and the side of length 2x + 2 as the third side of triangle.

So, by the property, we have :

n + x + 3 > 2x + 2

⇒ n > x - 1 ...........(2)

From both the equations (1) and (2) , We get :

x – 1 < n < 3x + 5

Therefore, The correct option is A. x – 1 < n < 3x + 5

4 0
2 years ago
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Have an amazing day :) <br> Will give brainlst! Pls help
Assoli18 [71]

Answer:

A. As the Study time in increases the Test score increases.

B. Yes, the relation appears linear. The data points lie mostly on a straight and noticeable line.

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3 years ago
In 376.924, what is the value of the 4
faust18 [17]
The thousandths place
4 0
3 years ago
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What are the x-coordinates for the maximum points in the function f(x) = 4 cos(2x − π) from x = 0 to x = 2π? (1 point) a x = 3 p
Ratling [72]

x-coordinates for the maximum points in any  function  f(x) by f'(x) =0 would be  x = π/2 and x= 3π/2.

<h3>How to obtain the maximum value of a function?</h3>

To find the maximum of a continuous and twice differentiable function f(x), we can firstly differentiate it with respect to x and equating it to 0 will give us critical points.

we want to find x-coordinates for the maximum points in any  function  f(x) by f'(x) =0

Given f(x)= 4cos(2x -π)

f'(x) = 0\\- 4sin(2x -\pi ) =0\\\\sin (2x -\pi ) =0 \\2x -\pi  = k\pi ...  k in Z

In general  x=(k+1)\pi /2

from x = 0 to x = 2π :

when k =0  then  x = π/2

when k =1  then x= π

when k =2  then x= 3π/2

when k =3  then x=2π

Thus, X-coordinates of maximum points are  x = π/2 and x= 3π/2

Learn more about maximum of a function here:

brainly.com/question/13333267

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