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4 years ago

How do you start a friends conversation in brainily

Mathematics

2 answers:

xeze [42]4 years ago

8 0

1 go to friends

2 click on their profile

3 click the speech icon

4 click start conversation

5 start texting them

enjoy

Agata [3.3K]4 years ago

5 0

Answer:

Maybe start with some jokes give brainliest have fun!

Then friend them!

You might be interested in

-1 over -7 rounded to the nearest tenth

Mazyrski [523]

Answer:

.1 or .14285714285on:

Step-by-step explanation

4 0

4 years ago

Read 2 more answers

PLEASE ANSWER ASAP

posledela

This is how you set up a percent of error proportion:
Amount of error x(Unknown percent)
Actual value = 100(Percents are out of hundreds)

So if you fill it in, it becomes 4 x
 80 =100
Cross multiply, 400= 80x.
Solve.
x=5 so percent error is 5%

5 0

3 years ago

13. Oscar's dog house is shaped like a tent. The slanted sides are both 5 feet

VashaNatasha [74]

Answer:

The height of the dog house = 4 feet.

Step-by-step explanation:

Given:

The shape of the dog house is like a tent.

The slant heights of the house is 5 feet.

The bottom of the house is 6 feet across.

To find the height of the dog house at its tallest point.

Solution:

On drawing the figure of the dog house in the shape of a tent, we find out that the tallest point would be at the midpoint of the bottom of the house.

Thus, we ave a right triangle, of which one leg = $\frac{6\ ft}{2}=3\ ft$ and hypotenuse = $5\ ft$

Applying Pythagorean theorem to find the measure of the other leg which is the height of the house.

$Hypotenuse^2=Leg1^2+Leg2^2$

Plugging in values.

$5^2=3^2+Leg2^2$

$25=9+Leg2^2$

Subtracting both sides by 9.

$25-9=9-9+Leg2^2$

$16=Leg2^2$

Taking square root both sides.

$\sqrt{16}=\sqrt{Leg2^2}$

$4=Leg2$

Thus, the height of the dog house = 4 feet.

6 0

4 years ago

Given: cosθ= -4/5 , sin x = -12/13 , θ is in the third quadrant, and x is in the fourth quadrant; evaluate tan 1/2 θ

mrs_skeptik [129]

Answer:

Step-by-step explanation:

If you're looking for what the half angle of the tangent of theta is, I'm a bit confused as to why you think the angle in the 4th quadrant, x, is relevant. But maybe you don't know it isn't and it's a "trick" to throw you off. Hmm...

Anyways, the half angle identity for tangent is

$tan(\frac{\theta}{2})=\frac{sin\theta}{1+cos\theta}$

There are actually 3 identities for the tangent of a half angle, but this one works just as well as either of the others do, so I'm going with this one.

If theta is in QIII, the value of -4 goes along the x axis and the hypotenuse is 5. That makes the missing side, by Pythagorean's Theorem, -3. Filling in our formula:

$tan(\frac{\theta}{2})=\frac{-\frac{3}{5} }{1+(-\frac{4}{5}) }$ which simplifies a bit to