How many time does 1/9 go in to 2

Here is a diagram that represents (3.1) ⋅ (1.4).

Firdavs [7]

Step-by-step explanation:

1. solution,

length of rectangle A(l)=3.1units

breadth of rectangle A(b)=1units

now,

area of rectangle A=l×b

=3.1units×1units

=3.1 sq units

2.solution,

length of rectangle B(l)=3.1units

breadth of rectangle B (b)=0.4units

now,

area of rectangleB=l×b

=3.1units×0.4units

=1.24 sq units

3.solution,

length=3.1units

breadth=1.4units

area =lxb

=3.1units x 1.4units

=4.34units

4 0

3 years ago

Read 2 more answers

A software developer wants to know how many new computer games people buy each year. Assume a previous study found the standard

Marrrta [24]

Answer:

The minimum sample size required to ensure that the estimate has an error of at most 0.14 at the 95% level of confidence is n=567.

Step-by-step explanation:

We have to calculate the minimum sample size n needed to have a margin of error below 0.14.

The critical value of z for a 95% confidence interval is z=1.96.

To do that, we use the margin of error formula in function of n:

$MOE=\dfrac{z\cdot \sigma}{\sqrt{n}}\\\\\\n=\left(\dfrac{z\cdot \sigma}{MOE}\right)^2=\left(\dfrac{1.96\cdot 1.7}{0.14}\right)^2=(23.8)^2=566.42\approx 567$

The minimum sample size to have this margin of error is n = 567.

3 0

3 years ago

Given: △EDN∼△LKI, DQ , KO are altitudes, DN=12, KI=4, DQ=KO+6. Find: QN and OI.

fgiga [73]

Answer:

QN = 3√7
OI = √7

Step-by-step explanation:

The ratio of corresponding sides DN and KI is 12 : 4 = 3 : 1. The same ratio applies to altitudes DQ and KO. Since the difference between these altitudes is 6 and the difference between their ratio units is 3-1 = 2, each ratio unit must stand for 6/2 = 3 units of linear measure. That is, ...

DQ = (3 units)·3 = 9 units

KO = (3 units)·1 = 3 units

Then the base lengths QN and OI can be found from the Pythagorean theorem:

KI² = KO² +OI²

4² = 3² +OI²

OI = √(16 -9)

OI = √7

QN = 3·OI = 3√7

8 0

3 years ago

Write down the bearing of: (a) Henly from Dinder (b) Dinder from Weare (c) Weare from Dinder (d) Weare from Henly (e) Dinder fro

Neko [114]

The bearing of the individuals from each other are as indicated below;

S45°E
N25°E
S65°E
S15°E
N45°E
N75°E

<h3>What is bearing of Henley from Dinder?</h3>

It follows from the task content that the bearing of the individuals from each other are expected to be determined.

a) For Henley from Dinder; it follows from observation that Henley is; S45°E of Dinder's position.

b) For Dinder from Weare; it follows from observation that Dinder is; N25°E of Weare's position.

c) For Weare from Dinder; it follows from observation that Weare is; S65°E of Dinder's position.

d) For Weare from Henly; it follows from observation that Weare is; S15°E of Dinder's position.

e) For Dinder from Henly; it follows from observation that Dinder is; N45°E of Henly's position.

f) For Henly from Weare; it follows from observation that Henly is; N75°E of Weare's position.