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Pachacha [2.7K]
3 years ago
10

How many time does 1/9 go in to 2

Mathematics
1 answer:
Hitman42 [59]3 years ago
5 0
It goes into 2 18 times
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12 and 13 please I’m giving 71 points
Pavlova-9 [17]

Answers and Step-by-step explanation:

12: The 5s are worth a lot more than the 2s. The 5s are worth fifty thousand and five thousand whereas the 2s are only worth two hundred and twenty.

13: She needs 4 forks (2000 - 1996 = 4)

    She needs 255 knives (2000 - 1745 = 255)

    She has 226 extra spoons ( 2116 - 2000 =  116)

5 0
3 years ago
Read 2 more answers
A quiz-show contestant is presented with two questions, question 1 and question 2, and she can choose which question to answer f
Mrrafil [7]

Answer:

The contestant should try and answer question 2 first to maximize the expected reward.

Step-by-step explanation:

Let the probability of getting question 1 right = P(A) = 0.60

Probability of not getting question 1 = P(A') = 1 - P(A) = 1 - 0.60 = 0.40

Let the probability of getting question 2 right be = P(B) = 0.80

Probability of not getting question 2 = P(B') = 1 - P(B) = 1 - 0.80 = 0.20

To obtain the better option using the expected value method.

E(X) = Σ xᵢpᵢ

where pᵢ = each probability.

xᵢ = cash reward for each probability.

There are two ways to go about this.

Approach 1

If the contestant attempts question 1 first.

The possible probabilities include

1) The contestant misses the question 1 and cannot answer question 2 = P(A') = 0.40; cash reward associated = $0

2) The contestant gets the question 1 and misses question 2 = P(A n B') = P(A) × P(B') = 0.6 × 0.2 = 0.12; cash reward associated with this probability = $200

3) The contestant gets the question 1 and gets the question 2 too = P(A n B) = P(A) × P(B) = 0.6 × 0.8 = 0.48; cash reward associated with this probability = $300

Expected reward for this approach

E(X) = (0.4×0) + (0.12×200) + (0.48×300) = $168

Approach 2

If the contestant attempts question 2 first.

The possible probabilities include

1) The contestant misses the question 2 and cannot answer question 1 = P(B') = 0.20; cash reward associated = $0

2) The contestant gets the question 2 and misses question 1 = P(A' n B) = P(A') × P(B) = 0.4 × 0.8 = 0.32; cash reward associated with this probability = $100

3) The contestant gets the question 2 and gets the question 1 too = P(A n B) = P(A) × P(B) = 0.6 × 0.8 = 0.48; cash reward associated with this probability = $300

Expected reward for this approach

E(X) = (0.2×0) + (0.32×100) + (0.48×300) = $176

Approach 2 is the better approach to follow as it has a higher expected reward.

The contestant should try and answer question 2 first to maximize the expected reward.

Hope this helps!!!

3 0
3 years ago
Rachel types
Art [367]

Answer:

4 im pretty sur

Step-by-step explanation:

7 0
3 years ago
PLZ HURRY Solve for g.<br><br>g3 – 1 &gt; 2
Phoenix [80]

g3 - 1 > 2

g3 - 1 + 1 > 2 + 1

g3 > 3

\frac{g3}{3} >  \frac{3}{3}

g  > 1

//

If the 3 is an exponent, then the person above me is right.

5 0
3 years ago
What is the prime factorization of 43? Enter your answer as a product of prime numbers, like 2 x 3 or as a single prime number,
storchak [24]

Answer:

43

Step-by-step explanation:

43 is a prime number

7 0
2 years ago
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