**Answer:**

**4x²+21x-2**

(OR)

**2x²-x-6**

**Step-by-step explanation:**

According to the Question,

Given, The difference Between two trinomials is x²-10x+2 & If one of the trinomials is 3x²-11x-4.

Let, Two Trinomials are P(x) = A & Q(x) = 3x²-11x-4

Then, P(x) - Q(x) = x²-10x+2

Put Value, We get

A - (3x²-11x-4) = x²-10x+2

A = x²-10x+2 + (3x²-11x-4)

A = x²-10x+2 + 3x²-11x-4

**A = 4x²+21x-2**

**(OR)**

If we Let, Two Trinomials are Q(x) = A & P(x) = 3x²-11x-4

Then, P(x) - Q(x) = x²-10x+2

Put Value, We get

(3x²-11x-4) - A = x²-10x+2

A = 3x²-11x-4 - (x²-10x+2)

A = 3x²-11x-4 - x²+10x-2

**A = 2x²-x-6**