Hey! here is the answer
<u>b³+c
</u>b²c²
Hi there!
When we have an equation standard form...

...the formula of the discriminant is
D = b^2 - 4ac
When
D > 0 we have two real solutions
D = 0 we have one real solutions
D < 0 we don't have real solutions
1.) Find the value of the discriminant and the the number of real solutions of
x^2-8x+7=0
Plug in the values from the equation into the formula of the discriminant

D > 0 and therefore we have two real solutions.
2.) Find the value of the discriminant and the number of real solutions of
2x^2+4x+2=0
Again, plug in the values from the equation into the formula of the discriminant.

D = 0 and therefore we have one real solution.
~ Hope this helps you.
Answer:
b>1
Step-by-step explanation:
-5b+8<3
-5b<3-8
-5b<-5
5b<5
b<5/5
b<1
b>1
Answer:
-2x + 10
Step-by-step explanation:
Distribute -2 to x - 5 to simplify the expression. So we get: -2(x - 5) = -2x + 10.