Answer with Step-by-step explanation:
Let the ones digit of the number be y
and tens digit of the number be x.
The tens digit is two less than the units digit.
i.e. x=y-2
The value of the number exceeds twice the sum of its digits by 19.
i.e. 10x+y=2(x+y)+19
10(y-2)+y=2(y-2+y)+19
10y-20+y=2(2y-2)+19
11y-20=4y-4+19
11y-4y=20-4+19
7y=35
dividing both sides by 7, we get
y=5
Putting value of y in x=y-2, we get
x=3
10x+y=10×3+5
=35
Hence, the two digit number is:
35
