All categories

4 years ago

Need help with 16, 19, 20, 21, A. B. C.

Mathematics

1 answer:

OleMash [197]4 years ago

3 0

16. .375 mi
19. 440 yards
20. 500 pounds
21. I don’t fw graphs : 3 hopes this helps sum

You might be interested in

red roses cost $3 each . Pink roses cost $2 each . A man buys 24 flowers for his wife with some pink roses and the rest red rose

katen-ka-za [31]

20 red roses and 4 pink roses

3 0

3 years ago

What is three blus six equal to <br><br><br><br>

gavmur [86]

Answer:

Three plus six: 3 * 6

When we multiply x*y, we are summing x times the same number: y ory times the same number.(x)

In our case, we are summing three times six, so: 6 + 6 + 6 = 18

We could also say we are summing six times three: 3 + 3 + 3 + 3 + 3 + 3 = 18

Nowwe can say that 6 * 3 = 18

5 0

3 years ago

Read 2 more answers

Classify the quadrilateral with the name that best describes it.

aev [14]

Answer:

the one on the top is a parrallelogram, the one on the bottom is a trapezoid

4 0

3 years ago

Working alone and at a constant rate, Machine A takes 3 hours to create a widget. Machine B, working alone and at a constant rat

PilotLPTM [1.2K]

Answer:

Time required by Machine B to create a widget = 4 hours

Step-by-step explanation:

Time taken by Machine A ( $T_{A}$ ) = 3 hours

Time taken by Machine B ( $T_{B}$ )= x hours

Time taken by both machines by working together = 12 hours

The time required to both machines by working together to finish a task is given by the formula = $\frac{T_{A} {T_{B} } }{T_{A} + T_{B} }$

Put the values in above formula we get

⇒ T = $\frac{3 x}{3 + x}$

⇒ 12 = $\frac{3 x}{3 + x}$

⇒ 36 + 12 x = 3 x

⇒ x = - 4 hours

This is the time required by Machine B to create a widget.

8 0

3 years ago

How to factor z²-4z+4

allochka39001 [22]

$\implies {\blue {\boxed {\boxed {\purple {\sf { \: ({ \: z - 2 \: })^{2} \: }}}}}}$

$\large\mathfrak{{\pmb{\underline{\orange{Step-by-step\:explanation}}{\orange{:}}}}}$

${z}^{2} - 4z + 4$

$= {z}^{2} - 2z - 2z + 4$

Taking " $z$ " as common from first two terms and " $2$ " from last two terms, we have

$= z \: ( \: z - 2 \: ) - 2 \: ( \: z - 2 \: )$

Taking the factor $(z-2)$ as common,

$= ( \: z - 2 \: )( \: z - 2 \: )$

$= {( \: z - 2 \: )}^{1 + 1}$

$= ({ \: z - 2 \: })^{2}$

$\red{\large\qquad \qquad \underline{ \pmb{{ \mathbb{ \maltese \: \: Mystique35❦}}}}}$

8 0

3 years ago