Greetings!Solve for <em>x</em>.
Distribute the Parenthesis. <em>How?</em> Multiply all of the terms inside the parenthesis by the number outside the parenthesis.
Add
6y to both sides.
Divide both sides by
-2.
The Answer Is:
Hope this helps.
-Benjamin
Divides el (1/2) q es 2 pq 2*1=2 y después multiplicas 2*2=4 entonces la respuesta es 4 y es base creo
Yes they are right. 2+784
Answer:
A =First term of the pattern = 11
To find the first five terms we have to use the rule which is
Add 10 to first term and then subtract 5 from it.Which is equivalent to
= A +10 -5
1. Second Term = 11 + 10 -5
= 21 - 5
=16
→Third term = 16 +10-5
= 26 - 5
= 21
→Fourth term : 21 + 10 - 5
= 31 -5
= 26
→Fifth term : 26 +10 -5
= 36- 5
= 31
→Sixth term:
=31 + 10- 5
= 41 -5
= 36
So, the first five term apart from 11 is 16, 21,26,31,36 which is an Airthmetic progression.
Step-by-step explanation:
a). A = {x ∈ R I 5x-8 < 7}
5x - 8 < 7 <=> 5x < 8+7 <=> 5x < 15 =>
x < 3 => A = (-∞ ; 3)
A ∩ N = {0 ; 1 ; 2}
A - N* = (-∞ ; 3) - {1 ; 2}
b). A = { x ∈ R I 7x+2 ≤ 9}
7x+2 ≤ 9 <=> 7x ≤ 7 => x ≤ 1 => x ∈ (-∞ ; 1]
A ∩ N = {0 ; 1}
A-N* = (-∞ ; 1)
c). A = { x ∈ R I I 2x-1 I < 5}
I 2x-1 I < 5 <=> -5 ≤ 2x-1 ≤ 5 <=>
-4 ≤ 2x ≤ 6 <=> -2 ≤ x ≤ 3 => x ∈ [-2 ; 3]
A ∩ N = {0 ; 1 ; 2 ; 3}
A - N* = [-2 ; 3) - {1 ; 2}
d). A = {x ∈ R I I 6-3x I ≤ 9}
I 6-3x I ≤ 9 <=> -9 ≤ 6-3x ≤ 9 <=>
-15 ≤ -3x ≤ 3 <=> -5 ≤ -x ≤ 3 =>
-3 ≤ x ≤ 5 => x ∈ [-3 ; 5]
A ∩ N = {0 ; 1 ; 2 ; 3 ; 4 ; 5}
A - N* = [-3 ; 5) - {1 ; 2 ; 3 ; 4}
