When y=2 and y=5
1. 2y-1 and (3y-5+y or 4y-5)
when y=2 ; 2(2)-1 = 3 and 4(2)-5=3
when y=5 ; 2(5)-1 = 9 and 4(5)-5=15
----nonequivalent-----
2.5y+4 and (7y+4-2y or 5y+4)
so you don't have to place any value in because 5y+4 and 7y+4-2y are equal,
whatever you place any value in, it will be all the same then
-----equivalent------
and no need to find more
v varies directly with height means
v/h=k were k is a constant
or also h/v=k where k is a constant (this is a different k than previous)
so if h=12 and v=300 then
h/v=12/300=1/25=k
so the relationhip could be h/v=1/25
if you di v/h, then
v/h=300/12=25/1=25=k
so the relationship could be v/h=25
Answer:
x= 1, -1
Step-by-step explanation:
1. true.
2. false.
3. false.
4. true.
these should be correct.
Step-by-step explanation:
Although I cannot find any model or solver, we can proceed to model the optimization problem from the information given.
the problem is to maximize profit.
let desk be x
and chairs be y
400x+250y=P (maximize)
4x+3y<2000 (constraints)
according to restrictions y=2x
let us substitute y=2x in the constraints we have
4x+3(2x)<2000
4x+6x<2000
10x<2000
x<200
so with restriction, if the desk is 200 then chairs should be at least 2 times the desk
y=2x
y=200*2
y=400
we now have to substitute x=200 and y=400 in the expression for profit maximization we have
400x+250y=P (maximize)
80000+100000=P
180000=P
P=$180,000
the profit is $180,000
