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Eduardwww [97]
2 years ago
10

Embryonic stem cells give rise to all cell types in the developing embryo. Would you expect the interphase period of stem cells

to be long or short?
Biology
2 answers:
timofeeve [1]2 years ago
6 0
The interphase period of stem cells would be short. This is because embryonic stem cells undergo rapid changes, so the interphase period would not be very long. If the entire cycle occurs during a short time period, then the interphase period is also short.
meriva2 years ago
4 0

I would expect the interphase period of stem cells to be short since embryonic stem cells undergo very rapid changes; thus interphase in them is short.

 

Embryonic<span> <span>stem </span>cells<span> (ES </span>cells) are pluripotent stem <span>cells </span>derived from the inner </span>cell<span> mass of a blastocyst, an early-stage pre implantation </span>embryo. Human embryos<span> reach the blastocyst stage 4–5 days post fertilization, at which time they consist of 50–150 </span>cells.

 

I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.

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The greenhouse effect:

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7 0
3 years ago
What is the name of the area around a charged object where the object can exert a force on other charged objects?
dolphi86 [110]
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2 years ago
Read 2 more answers
Una solución de 0.204 M de NaOH seutiliza para neutralizar 50 mL de una solución de H3PO4. Si se necesitaron 16.4 mL de la soluc
vfiekz [6]

Answer: 0.05 M

Explanation:

Para responder esta pregunta, hay que tener en cuenta la Ley de Conservación de la Masa. <u>La misma indica que en una reacción química en un sistema cerrado, la masa total de las moléculas que participan permanece constante.</u> Esto significa que la masa utilizada en los reactivos es la misma que la masa de los productos generados.

En este problema, se cuenta con una solución de NaOH (hidróxido de sodio) tiene una molaridad de 0.204 (siendo la molaridad el número de moles por litro de solución) y se utilizan 16.4 mL de dicha solución para agregarla a 50 mL de una solución de H3PO4 (ácido fosfórico).

Entonces, ya que la masa de ambas soluciones no se pierde, podemos utilizar la ecuación de la Ley de Conservación de la Masa:

Concentración inicial x Volumen inicial = Concentración final x Volumen final.

Concentración inicial: 0.204 M

Volumen inicial: 16.4 mL

Concentración final: ?

Volumen final: 50 mL + 16.4 mL = 66.4 mL

Reemplazamos los valores en la ecuación:

0.204 M x 16.4 mL = Concentración final x 66.4 mL

La molaridad de la solución de H3PO4 es de 0.05 M.

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3 years ago
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Answer:

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Explanation:

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PLEASE HELP!! 50 POINTS!
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