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Bess [88]
3 years ago
15

3yards per second in miles per hour

Mathematics
1 answer:
Amanda [17]3 years ago
3 0
3 yards per second is 6.136364 mph.

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How do I solve equations with a variable to the power of something (give steps please)
lozanna [386]

Answer:

Step-by-step explanation:

Factoring will reveal the solution. So we divide the equation by the greatest common factor of the terms and use that factor as the coefficient. In this case the greatest common factor is just x.

2x^2+5x

x(2x+5) so the equation will equal zero when either of those expressions is zero because zero times anything is zero. x=0 and x=-5/2

5 0
3 years ago
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The inequality 10.45b + 56.50 < 292.67 is used to find the number of boxes (b) that can be loaded on a truck without exceedin
PSYCHO15rus [73]
We solve the inequality by subtracting 56.50 from both sides of the equation,
                                10.45b + 56.50 - 56.50 < 292.67 - 56.50 
                                        10.45b < 236.17
Then, divide both sides of the inequality by 10.45
                                             b < 22.6
The solution suggests that the number of boxes than can be loaded on a truck without exceeding the weight limit of the truck should always be lesser than 22.6. Since we are talking about number of boxes, the maximum number of boxes that can be loaded should only be 22. 
6 0
3 years ago
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Combine each pair of equations solve the combined equation 3j +14=-5z-10j=5z
ArbitrLikvidat [17]

Given data:

The first equation is 3j +14=-5z.

The second equation is -10j=5z​ .

Add both the equations.

\begin{gathered} (3j+14)+(-10j)=-5z+5z \\ -7j+14=0 \\ 7j=14 \\ j=2 \end{gathered}

Substitute 2 for j in the first equation.

\begin{gathered} 3(2)+14=-5z \\ 20=-5z \\ z=-4 \end{gathered}

Thus, the value of j is 2 and z is -4.

3 0
1 year ago
I need help plz plz plz
yan [13]

Step-by-step explanation:

The answer is

X=23

Hope it helpsss

8 0
3 years ago
CAN somebody plz plz help me with raios
Kaylis [27]
I can help what are the problems
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3 years ago
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