Answer:
The length is 56 and the width is 54.
Step-by-step explanation:
The perimeter of a rectangle is 2x+2y (width and length on both sides). so 2x+2y=220. Also x=y-2, because the width is 2 feet less than the length. Fill x=y-2 in 2x+2y=220 and we get 2(y-2)+2y=220. 2y-4+2y=220. 4y=216. y=54. Fill in y=54 in 2x+2y=220 and we get 2x+2(54)=220. 2x=220-2(54)=112. x=56.
Answer:
A. Answer is 2263.
Checkpoint 1 is -86 Checkpoint 4 is 2177
Subtract -86 from 2177....2177-(-86)
=2263
2263 is how much higher checkpoint 1 (-86) is from checkpoint 4 (2177)
B. 239 FEET.
the altitude of the hill must be subtracted by the depth of the ckeckpoint(2)(-189)
therefore the altitude of the hill comes out to be 428-189=239feet.
therefore,the actual altitude of the hill is 239 feet.
The answer would be ay-xb
7/4 is the answer to your question
