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lys-0071 [83]
3 years ago
12

What is another way to write 4 hundreds

Mathematics
2 answers:
slega [8]3 years ago
6 0
400=four \ hundred \\ \\ 4*100 \\ \\ 200*2 \\ \text{Good look!!!}
masya89 [10]3 years ago
4 0

400 or .004 or four hundreds


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Standard form for -10-6x^4-7x^2+5x
qaws [65]
-6x^4-7x^2+5x-10. hope this helps ! :)
7 0
2 years ago
How do you graph the equation f(x)=10x+40??
irga5000 [103]
Ok so linear equations come in the form
y = mx + b

B is the y-intercept. In this equation the y intercept is 40. A y- intercept is where the graph crosses the y axis so at the point (0,40) the graph crosses the y axis.

M is the slope which is rise over run so if the slope was 10 (which it is) 10 is equivalent to 10/1 so you move up 10 units for every 1 unit you move across.

So to graph this equation, you would draw your first point at (0,40). For your next point, you would move right one unit, and up 10 units. Draw a point there which would be (1, 50). Hopefully you understand. For going left from the y intercept point, you would move left 1 and down 10.

Actual graph above.

Hope this helps C:

8 0
2 years ago
Here is a list of numbers: 13, 15, -6, 8, -16, 2, -12 ,3 ,-18 ,-18 state the median.
DiKsa [7]

The median of list of numbers is-2.

Given the list of numbers is 13,15,6,8,-16,2,-12,3,-18,-18.

The median is the median of a sorted list of numbers. To find the median of a sequence of numbers, the numbers must be sorted in order from lowest to highest or highest to lowest.

Firstly, we will arrange the number from ascending to descending, we get

-18,-18,-16,-12,-6,2,3,8,13,15.

Now, we will find the middle term of the sequence, we get

The middle terms are -6 and 2.

Further, we will find the median of it.

n=(-6+2)/2

n=-4/2

n=-2

Hence, the median of the list of numbers 13, 15, -6, 8, -16, 2, -12 ,3 ,-18 ,-18 is -2.

Learn more about median from here brainly.com/question/15796951

#SPJ4

7 0
2 years ago
What is the length of PC?
marshall27 [118]
<span>31 trillion kilometers or 19 trillion miles.</span>
7 0
3 years ago
(1 point) A random sample of 600 movie goers in Flagstaff found 252 movie goers who had bought popcorn on their last visit. Find
garik1379 [7]

<u>Answer-</u>

A 95% confidence interval for the true percent of movie goers is 36.41% to 44.25%

<u>Solution-</u>

Given,

n = 600 (sample size)

x = 252 (number of people who bought)

Confidence interval = 95%, so z = 1.96

We know that,

\mu = M\pm Z(SE)

where,

M = sample mean

Z  = Z statistic determined by confidence level

SE = standard error of mean

Calculating the values,

M=\frac{x}{n} =\frac{242}{600} =0.4033

Z=1.96 from the tables

SE=\sqrt{\frac{M\times (1-M)}{n}}

\Rightarrow SE=\sqrt{\frac{0.4033\times (1-0.4033)}{600}}=0.02

Putting all the values in the formula,

\mu = M\pm Z(SE)

\mu = 0.4033\pm 1.96(0.02)

=0.4033\pm 0.0392

=0.4425, 0.3641

= 44.25\%,36.41\%

5 0
3 years ago
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