9514 1404 393
Answer:
C. $1.50
Step-by-step explanation:
The graph is a straight line through the origin, so the revenue is proportional to the number of tickets. The ratio of revenue to tickets will tell you the money raised for each ticket sold. Pick any point on the graph and divide the revenue value by the number of tickets.
The division can be easy if the number of tickets is 10. We see that the revenue for 10 tickets is $15, so the amount raised for each ticket is ...
$15/10 = $1.50 . . . . raised per ticket sold
Answer: 20%
Step-by-step explanation: Since the number changes from 15 to 18, it's getting bigger which means it increases. To find the percent increase, we use the formula shown.
The amount of change is the difference between the two numbers. In this case, we would subtract 18 - 15 which equals 3. Then, we put 3 over our original number which is 15.
3 ÷ 15 = 0.2
Now, we need the percent increase which means we need to write 0.2 as a percent by moving the decimal point two places to the right to get 20%.
Therefore, the percent increase is 20%
This is quite difficult to try to explain so I'm going to set up some matrices to demonstrate as best as I can. If matrix A has 3 rows and 2 columns, it would be respresented as
![A_{3*2}](https://tex.z-dn.net/?f=%20A_%7B3%2A2%7D%20)
. This matrix can only be multiplied by another matrix that has the same number off rows as the number of columns in A. For example, if matrix B has 2 rows and 3 columns, it would be represented as
![B_{2*3}](https://tex.z-dn.net/?f=%20B_%7B2%2A3%7D%20)
. If we set them next to each other, it might be easier to see the rule:
![A_{3*2} B_{2*3}](https://tex.z-dn.net/?f=%20A_%7B3%2A2%7D%20B_%7B2%2A3%7D%20%20)
. The 2's match, and the other numbers represent how your solution matrix will look. Your solution matrix will be a 3x3. Here is matrix A:
![\left[\begin{array}{ccc}1&2\\3&4\\5&6\end{array}\right]](https://tex.z-dn.net/?f=%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%262%5C%5C3%264%5C%5C5%266%5Cend%7Barray%7D%5Cright%5D%20)
and here's B:
![\left[\begin{array}{ccc}1&2&3\\4&5&6\\\end{array}\right]](https://tex.z-dn.net/?f=%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%262%263%5C%5C4%265%266%5C%5C%5Cend%7Barray%7D%5Cright%5D%20)
. We can multiply these according to the rules. The multiplication works like this:
![\left[\begin{array}{ccc}1&2\\3&4\\5&6\end{array}\right] * \left[\begin{array}{ccc}1&2&3\\4&5&6\\\end{array}\right]](https://tex.z-dn.net/?f=%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%262%5C%5C3%264%5C%5C5%266%5Cend%7Barray%7D%5Cright%5D%20%2A%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%262%263%5C%5C4%265%266%5C%5C%5Cend%7Barray%7D%5Cright%5D%20)
. first row of A times first column of B: (1*1)+(2*4) = 9. that goes into row 1 column 1 of your solution matrix. Go va to row 1 in A but column 2 in B: (1*2)+(2*5) = 12. That goes into row 1 column 2 of your solution matrix. Next row 1 of A and column 3 of B: (1*3)+(2*6) = 15. That goes into the first row column 3 of the solutiong matrix. Now move to row 2 of A column 1 of B: (3*1)+(4*4) = 19. That goes into row 2 column 1 in your solution matrix. Next row 2 A, column 2 B: (3*2)+(4*5) = 26. That goes into row 2 column 2 solution matrix. Continue as I showed you. You should be fine.