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4 years ago

How do I solve this?

Mathematics

1 answer:

Yuki888 [10]4 years ago

3 0

The answer is B. The values of y must only be positive because it is equal to
$| - x|$
The other options states that the values of y could be negative which is why it is wrong.

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What is the 2 out of 4

Vlad [161]

It is 2 !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

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3 years ago

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a car needw fixing and abe can fix it for $70 per hour with a $130 part, but gabe can fix it for $80 an hour with a $40 part. ho

Zolol [24]

70 + 130 = 200
This would be Abe’s one hour of work and the part
80 + 80 + 40 = 200
This would be Gabe’s two hours of work and the part

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3 years ago

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-4x - 2 = -18 POR FA AYUDENME

charle [14.2K]

Answer:

The answer is x=4

Step-by-step explanation:

so you have -4x-2=-18

so we get rid of -2 by adding it to the other side so you'll end up having -4x=-16

you then divide that by -4 on both sides and get x=4 as your remaining answer

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3 years ago

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Please answer There is a bag filled with 3 blue and 5 red marbles. A marble is taken at random from the bag, the colour is noted

Misha Larkins [42]

Answer:

$\frac{15}{28}$ is the required probability.

Step-by-step explanation:

Total number of Marbles = Blue + Red $= 3 + 5 = 8$

Probability of getting blue $= \frac{3}{8}$

Probability of not getting a blue $=\frac{5}{8}$

To get exactly one blue in two draws, we either get a blue, not blue, or a not blue, blue.

<u>First Draw Blue, Second Draw Not Blue:</u>

1st Draw: $P(Blue) = \frac{3}{8}$

2nd Draw: $P(Not\:Blue)=\frac{5}{7}$ (since we did not replace the first marble)

To get the probability of the event, since each draw is independent, we multiply both probabilities.

$P(Event)=\frac{3}{8}\cdot \frac{5}{7}=\frac{15}{56}$

<u>First Draw Not Blue, Second Draw Not Blue:</u>

1st Draw: $P(Not\:Blue)=\frac{5}{8}$

2nd Draw: $P(Not\:Blue)=\frac{3}{7}$ (since we did not replace the first marble)

To get the probability of the event, since each draw is independent, we multiply both probabilities.

$P(Event)=\frac{5}{8}\cdot \frac{3}{7}=\frac{15}{56}$

To get the probability of exactly one blue, we add both of the events:

$\frac{15}{56}+\frac{15}{56}=\frac{15}{28}$

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3 years ago

Which weighs the least 2 centigrams 2 grams 2 hectograms 2 kilograms or 2 milligrams

Mekhanik [1.2K]

To answer the question above, use conversion factors and dimensional analysis. In this given, it is easier to use grams as the basis.

a. (2 centrigrams) x (1 gram / 100 centigrams) = 0.02 grams
b. 2 grams
c. (2 hectograms) x (1 gram / 0.01 hectogram) = 200 grams
d. (2 kilograms) x (1 gram / 0.001 kilogram) = 2000 grams
e. (2 milligrams) x (1 gram / 1000 millimeters) = 0.002 grams

Thus, the answer is 2 milligrams.

7 0

3 years ago