To answer this kind of question, you need to insert the first equation into second equation or vice versa. The equation from the question should be:
1. 3 paperback books + 5 hardcover book = $80.10
2. 7 paperback books + 4 hardcover book= $100.65
It would be easier to convert the 1st equation into
5 hardcover book = $80.10- 3 paperback books
hardcover book= $16.02- 0.6 paperback books
Then insert it to 2nd equation:
7 paperback books + 4 ($16.02- 0.6 paperback books)= $100.65
7 paperback books + $64.08- 2.4 paperback books= $100.65
4.6 paperback books = $100.65- $64.08= $36.57
paperback book= $7.95
Insert paperback book price to the first equation to find the hardcover book price
3 paperback books + 5 hardcover book = $80.10
3 ($7.95)+ 5 hardcover book = $80.10
5 hardcover book = $80.10 - $23.85= $56.25
hardcover book = $11.25
Then one paperback and one hardcoverbook= $7.95 + $11.25= $19.20
Answer:

Step-by-step explanation:
Given:


To Find:

Solution
Substituting the above values we get

Now make both the denominator same by multiplying and dividing by 3 to the first term so we get

∴ 
10 × 30 = 300
(20 characters thing)
Answer:
The Division Property of Equality
Step-by-step explanation:
<u>The Addition Property of Equality:</u> When you add something to one side of the equation, you must add the same thing to the other side.
<u>The Subtraction Property of Equality:</u> When you subtract something from one side of the equation, you must subtract the same thing from the other side.
<u>The Multiplication Property of Equality:</u> When you multiply something to one side of the equation, you must multiply the same thing to the other side.
<u>The Division Property of Equality:</u> When you divide something from one side of the equation, you must divide the same thing from the other side.
In this case, you have to divide both sides of the equation by 5 to get x = 4. That means that the division property of equality was used.
I hope this helps! Have a great day!
Answer:

Step-by-step explanation:
This table will prove to be helpful to find the probability that a student has a cell phone and is from School B.
First off, we know that a total of 1000 students were interviewed, both from School A and from School B.
We also know that 479 of those 1000 were from School B (total on the right).
Looking further into School B, we can see that 408 students from school B have a cell phone.
Therefore, we can find the probability by finding 408 / 1000.

Therefore, the probability that a randomly selected student is from School B <em>and</em> has a phone is 0.41, or 41%.
Hope this helped!