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jekas [21]
3 years ago
14

Simplify the expression. (a^3/2)^3

Mathematics
1 answer:
Archy [21]3 years ago
3 0

Answer:

a^6/8

Step-by-step explanation:

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2,000 water bottles are being labeled and boxed. Each box holds 6 water bottles. How many bottles will be left over?
Lostsunrise [7]

Answer:

2 left out, with 333 boxes

Step-by-step explanation:

2000/6=333.333333 (\frac{1}{3})

\frac{1}{3} of 6 is 2. Therefore, there would be 333 boxes, with two left unboxed.

4 0
3 years ago
Read 2 more answers
How much candy at $1.16 a pound should be mixed with candy worth 86 cent a pound in order to obtain a mixture of 60 pounds of ca
vovangra [49]
Let the weights of the two candies be repres. by x and y.

Then x + y = 60, or x = 60 - y

($1.16 / lb) x + ($0.86 / lb) y = ($1.00 / lb) (60 lb) = $60

Then 1.16(60-y) + 0.86y = 60
   69.6 - 1.16y + 0.86y = 60                                9.6
     9.6 = 0.3y                         Solving for y, y = ------- = 32 lb
                                                                            0.3

                                               Then x = (60-32) lb = 28 lb
5 0
3 years ago
Read 2 more answers
Find the number that makes the ratio equivalent to 4:9.
Talja [164]
2:4.5

I divided by two
7 0
3 years ago
Need rn. worth 30.
Likurg_2 [28]

Considering the situation described, the confidence interval is given by:

(0.35, 0.51).

<h3>What is a confidence interval?</h3>

It is given by the <u>estimate plus/minus the margin of error</u>.

For this problem, we have that:

  • The estimate is of 0.43.
  • The margin of error is half the range of the observations, hence M = (0.48 - 0.32)/2 = 0.08.

Then, the bounds of the interval are given by:

  • 0.43 - 0.08 = 0.35.
  • 0.43 + 0.08 = 0.51.

More can be learned about confidence intervals at brainly.com/question/25890103

#SPJ1

4 0
2 years ago
Write the rule for the nth term of the following sequence.
denis-greek [22]

Answer:

2^{n-3} is the nth term of the given sequence.

Step-by-step explanation:

The sequence given is

\frac{1}{4},\frac{1}{2},1,2,4 .....

We can clearly see that 1st term is \frac{1}{4} and 2nd term is \frac{1}{2}

2nd term is obtained by multiplying the 1st term by 2.

2nd term is \frac{1}{2} and 3rd term is 1.

3rd term is obtained by multiplying the 2nd term by 2.

3rd term is 1 and 4th term is 2.

4th term is obtained by multiplying the 3rd term by 2.

Clearly, the given series is a <em>Geometric Progression(GP)</em> with

First term, a = \frac{1}{4}

Common Ratio, r = 2

We know that n^{th} term for a GP is:

a_n = ar^{n-1}

Putting values of <em>a</em> and <em>r</em>

a_n = \dfrac{1}{4}2^{n-1}\\a_n = \dfrac{1}{2^{2} }2^{n-1}\\a_n = 2^{n-1-2}\\a_n = 2^{n-3}

Hence, 2^{n-3} is the nth term of the given sequence.

3 0
3 years ago
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