Answer:
2 left out, with 333 boxes
Step-by-step explanation:
2000/6=333.333333 (
)
of 6 is 2. Therefore, there would be 333 boxes, with two left unboxed.
Let the weights of the two candies be repres. by x and y.
Then x + y = 60, or x = 60 - y
($1.16 / lb) x + ($0.86 / lb) y = ($1.00 / lb) (60 lb) = $60
Then 1.16(60-y) + 0.86y = 60
69.6 - 1.16y + 0.86y = 60 9.6
9.6 = 0.3y Solving for y, y = ------- = 32 lb
0.3
Then x = (60-32) lb = 28 lb
Considering the situation described, the confidence interval is given by:
(0.35, 0.51).
<h3>What is a confidence interval?</h3>
It is given by the <u>estimate plus/minus the margin of error</u>.
For this problem, we have that:
- The margin of error is half the range of the observations, hence M = (0.48 - 0.32)/2 = 0.08.
Then, the bounds of the interval are given by:
More can be learned about confidence intervals at brainly.com/question/25890103
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Answer:
is the nth term of the given sequence.
Step-by-step explanation:
The sequence given is

We can clearly see that 1st term is
and 2nd term is
2nd term is obtained by multiplying the 1st term by 2.
2nd term is
and 3rd term is 1.
3rd term is obtained by multiplying the 2nd term by 2.
3rd term is 1 and 4th term is 2.
4th term is obtained by multiplying the 3rd term by 2.
Clearly, the given series is a <em>Geometric Progression(GP)</em> with
First term, 
Common Ratio,
We know that
term for a GP is:

Putting values of <em>a</em> and <em>r</em>

Hence,
is the nth term of the given sequence.