=8x + (-3) (5) + (-3) (9x)
=8x + -15 + -27x
=8x + -15 + -27x
(8x + -27x) + (-15)
19x +-15
19x -15
The correct answer is H correct me if I’m wrong but I looked it up also branilest plz
So the solid consist of 1 pentagon, 5 congruent equilateral triangle and 5 congruent squares and has 11 vertices so the number of edges of this solid is 20. I hope you are satisfied with my answer and feel free to ask form more if you have more clarifications.
Answer:
8.20in³
Step-by-step explanation:
Given V = πr²h
r is the radius = 1.5in
h is the height = 6in
thickness of wall of the cylinder dr = 0.04in
top and bottom thickness dh 0.07in+0.07in = 0.14in
To compute the volume, we will find the value of dV
dV = dV/dr • dr + dV/dh • dh
dV/dr = 2πrh
dV/dh = πr²
dV = 2πrh dr + πr² dh
Substituting the values into the formula
dV = 2π(1.5)(6)•(0.04) + π(1.5)²(6) • 0.14
dV = 2π (0.36)+π(1.89)
dV = 0.72π+1.89π
dV = 2.61π
dV = 2.61(3.14)
dV = 8.1954in³
Hence volume, in cubic inches, of metal in the walls and top and bottom of the can is 8.20in³ (to two dp)
Distribute 5/7 through the parentheses and add like terms after.
Answer: 11/7x + 11/35y
