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ANTONII [103]
3 years ago
9

All sides of the building shown above meet at right angles. If three of the sides measure 2 meters, 7 meters, and 11 meters as s

hown, then what is the perimeter of the building in meters?

Mathematics
1 answer:
Svetach [21]3 years ago
3 0

Answer:

Perimeter= 40 units

Step-by-step explanation:

Ok

We are asked to look for the perimeter.

We have some clue given.

All at right angle and some sides are given it's full length.

We have the bae to be 11 unit

The height to be 7 unit.

What this mean is that taking either the base or the height should sum up to either 11 or 7 respectively.

Let's go for the other side of the height.

Let's take all the vertical height and sum it up to 7 because the right side is equal to 7.

So we have 7+7+11

But it's not complete yet.

We are given a dimension 2.

And the 2 is in two places so it's total 2*2= 4

The two is for a small base .

The base is actually an extra to the 11 of the other base.

So summing up

We have 2*11 + 2*7 + 2*2

Perimeter= 22+14+4

Perimeter= 40 units

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<h3>How to determine the equivalent expression?</h3>

The logarithmic expression is given as:

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The law of logarithm states that:

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This means that the expression can be split as:

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Hence, the equivalent expression of \log_c(\frac{x^2 - 1}{5x}) is \log_c(x^2 - 1) - \log_c(5x)

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An auto mechanic converts a metric part to 0.492 in. The part comes only in fractional sizes given to the nearest 64th of an inc
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