![(x+5)(x-3)[x-(4-i)][x-(4+i)] \\ (x^{2}+5x-3x-15)(x-4+i)(x-4-i) \\ (x^{2}+5x-3x-15)(x^{2} -4x-xi-4x+16+4i+xi-4i- i^{2} ) \\ (x^{2}+5x-3x-15)( x^{2} -8x+16- i^{2}) \\ (x^{2}+5x-3x-15)( x^{2} -8x+16-(-1)) \\ (x^{2}+5x-3x-15)( x^{2} -8x+16+1) \\ (x^{2}+5x-3x-15)( x^{2} -8x+17)](https://tex.z-dn.net/?f=%28x%2B5%29%28x-3%29%5Bx-%284-i%29%5D%5Bx-%284%2Bi%29%5D%0A%20%5C%5C%20%0A%28x%5E%7B2%7D%2B5x-3x-15%29%28x-4%2Bi%29%28x-4-i%29%0A%5C%5C%0A%28x%5E%7B2%7D%2B5x-3x-15%29%28x%5E%7B2%7D%20-4x-xi-4x%2B16%2B4i%2Bxi-4i-%20i%5E%7B2%7D%20%29%0A%5C%5C%0A%28x%5E%7B2%7D%2B5x-3x-15%29%28%20x%5E%7B2%7D%20-8x%2B16-%20i%5E%7B2%7D%29%0A%5C%5C%0A%28x%5E%7B2%7D%2B5x-3x-15%29%28%20x%5E%7B2%7D%20-8x%2B16-%28-1%29%29%0A%5C%5C%0A%28x%5E%7B2%7D%2B5x-3x-15%29%28%20x%5E%7B2%7D%20-8x%2B16%2B1%29%0A%5C%5C%0A%28x%5E%7B2%7D%2B5x-3x-15%29%28%20x%5E%7B2%7D%20-8x%2B17%29)
From there just distribute and simplify.
50. since n_1/4<1 the equation is not true. it has no solution.
48. same thing since 45 <= z the equation is not true.
1:21 divide both digits by 9
Answer:
2/7
Step-by-step explanation:
There are 22 (12 + 10) total students in the class. That means that the chance of the first student picked being a girl is 12/22.
Now, we must calculate the chance of the next student to be picked <em>also </em>being a girl - however, there is a trap here! Remember that since a girl has been picked, the total student pool has decreased to 21 and and the total number of girls has decreased to 11. This means the new chance of girl being picked is 11/21.
To find the probability of both these events happening in conjunction, these fractions must be multiplied. 12/22 * 11/21 = 132/462, which simplifies to 2/7.
Answer:
The length of each side is 31.5m, 26.5m, 7m
Step-by-step explanation:
Let the length of the first side of the triangle be x meters.
Then, the second side is x-5 meters.
The third side is given as 7 meters.
The perimeter is 65 meters
This gives us the equation:
The length of each side is 31.5m, 26.5m, 7m
