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Marysya12 [62]
2 years ago
11

Please Help Algebra II

Mathematics
1 answer:
harkovskaia [24]2 years ago
8 0
The student buys 3 small notebooks and 3 large notebooks
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How do you solve this problem? 4a-3b+7a=
Inessa05 [86]
In this problem, you combine the like terms...

4a - 3b + 7a

4a and 7a are like terms so you add them together.

4a + 7a = 11a

So, the answer is: 11a - 3b
3 0
2 years ago
Which of the following is the parent function of all absolute value functions?
jeyben [28]

Answer:

The parent function is f(x) = |x|

Step-by-step explanation:

Option 1 and 4 are not absolute value, and option 3 has a number before it making it changed.

3 0
3 years ago
I have some geometry questions today!
vagabundo [1.1K]

Answer:

<h3>Question 7</h3>

<u>Arc LM has length of:</u>

  • LM = 2πr*72/360
  • LM = 2π*1*1/5
  • LM = 2π/5
<h3>Question 8</h3>

<u>Area of the given sector:</u>

  • πr²*θ/360 =
  • x²π*(360 - 75)/360 =
  • x²π(19/24) =
  • 19πx²/24

5 0
2 years ago
Solve the equation below
Elina [12.6K]

Answer:

(-5,3)

Step-by-step explanation:

-40+8y=-16

8y=24

y=3

7 0
2 years ago
Read 2 more answers
I could use some more help
kherson [118]

Answer:

\left[\begin{array}{ccc}-30&22&8\\-4&-4&16\\30&-28&18\end{array}\right]

Step-by-step explanation:

Given

A = \left[\begin{array}{ccc}-1&9&2\\10&-10&2\\-5&6&-5\end{array}\right]

B = \left[\begin{array}{ccc}7&-1&-1\\6&-4&-3\\-10&10&-7\end{array}\right]

Required

2A - 4B

To solve 2A - 4B, we first multiply matrix A by 2 and matrix B by 4

So, if

A = \left[\begin{array}{ccc}-1&9&2\\10&-10&2\\-5&6&-5\end{array}\right]

2A = 2 *\left[\begin{array}{ccc}-1&9&2\\10&-10&2\\-5&6&-5\end{array}\right]

2A = \left[\begin{array}{ccc}-2&18&4\\20&-20&4\\-10&12&-10\end{array}\right]

If

B = \left[\begin{array}{ccc}7&-1&-1\\6&-4&-3\\-10&10&-7\end{array}\right]

then

4B = 4*\left[\begin{array}{ccc}7&-1&-1\\6&-4&-3\\-10&10&-7\end{array}\right]

4B = \left[\begin{array}{ccc}28&-4&-4\\24&-16&-12\\-40&40&-28\end{array}\right]

So; 2A - 4B becomes

\left[\begin{array}{ccc}-2&18&4\\20&-20&4\\-10&12&-10\end{array}\right] - \left[\begin{array}{ccc}28&-4&-4\\24&-16&-12\\-40&40&-28\end{array}\right]

\left[\begin{array}{ccc}-2-28&18-(-4)&4-(-4)\\20-24&-20-(-16)&4-(-12)\\-10-(-40)&12-40&-10-(-28)\end{array}\right]

\left[\begin{array}{ccc}-30&18+4&4+4\\20-24&-20+16&4+12\\-10+40&12-40&-10+28\end{array}\right]

\left[\begin{array}{ccc}-30&22&8\\-4&-4&16\\30&-28&18\end{array}\right]

Hence, 2A - 4B is equivalent to

\left[\begin{array}{ccc}-30&22&8\\-4&-4&16\\30&-28&18\end{array}\right]

3 0
2 years ago
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