Answer:
imaginary roots
Step-by-step explanation:
For a quadratic in the form ...
![ax^2+bx+c=0](https://tex.z-dn.net/?f=ax%5E2%2Bbx%2Bc%3D0)
the discriminant is ...
![d=b^2-4ac](https://tex.z-dn.net/?f=d%3Db%5E2-4ac)
You have a=1, b=-6, c=12, so the discriminant is ...
d = (-6)² -4(1)(12) = 36 -48 = -12
When the discriminant is negative, both roots are complex. When the discriminant is not a perfect square, both roots are irrational. Here, the discriminant is negative and not a perfect square, so the roots are complex with an irrational imaginary part.
The best single descriptor is <em>imaginary root</em>.
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The roots are (-b±√d)/(2a) = (6 ± 2i√3)/2 = 3 ± i√3. These roots have a rational real part and an irrational imaginary part. When the number with an imaginary part has a non-zero real part, it is called "complex", rather than "imaginary."