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Aliun [14]
3 years ago
9

Use the discriminant to describe the roots of each equation. Then select the best description. x2 - 6x + 12 = 0 double root real

and rational root real and irrational root imaginary root
Mathematics
1 answer:
Alona [7]3 years ago
3 0

Answer:

  imaginary roots

Step-by-step explanation:

For a quadratic in the form ...

  ax^2+bx+c=0

the discriminant is ...

  d=b^2-4ac

You have a=1, b=-6, c=12, so the discriminant is ...

  d = (-6)² -4(1)(12) = 36 -48 = -12

When the discriminant is negative, both roots are complex. When the discriminant is not a perfect square, both roots are irrational. Here, the discriminant is negative and not a perfect square, so the roots are complex with an irrational imaginary part.

The best single descriptor is <em>imaginary root</em>.

_____

The roots are (-b±√d)/(2a) = (6 ± 2i√3)/2 = 3 ± i√3. These roots have a rational real part and an irrational imaginary part. When the number with an imaginary part has a non-zero real part, it is called "complex", rather than "imaginary."

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6 0
3 years ago
Is 54 divided by 6 equal 0.09
Thepotemich [5.8K]
No the answer is 9 because 54 divided by 9 is 9
4 0
3 years ago
Read 2 more answers
Can you guys help me with this?
Ghella [55]
F(x)=2x^2-x-6
Factoring:
f(x)=2(2x^2-x-6)/2=(2^2x^2-2x-12)/2=[(2x)^2-(2x)-12]/2
f(x)=(2x-4)(2x+3)/2=(2x/2-4/2)(2x+3)→f(x)=(x-2)(2x+3)

g(x)=x^2-4
Factoring
g(x)=[sqrt(x^2)-sqrt(4)][sqrt(x^2)+sqrt(4)]
g(x)=(x-2)(x+2)

f(x)/g(x)=[(x-2)(2x+3)] / [(x-2)(x+2)
Simplifying:
f(x)/g(x)=(2x+3)/(x+2)

Answer: Third Option (2x+3)/(x+2)
7 0
3 years ago
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