Heinepkenirnrid Help

What is the slope of this line? A. 3 B. -1/3 C. -3 D. -2 E. 4

Bingel [31]

Answer:

-3

Step-by-step explanation:

Pick two points on the graph, lets go with (0, 4) and (1, 1)

y = mx + b

m is the slope and to figure it out use below formula

m = (y₂ - y₁) / (x₂ - x₁)

= (1 - 4) / (1 - 0)

= -3 / 1

= -3

5 0

3 years ago

Read 2 more answers

What is (4a²)³÷8a²? can you please answer in normal number form (not like 3²)

AleksandrR [38]

Answer:

$8a^4$

Step-by-step explanation:

Hello! $(4a^2)^3=4\cdot4\cdot4\cdot a^2\cdot a^2\cdot a^2=64a^6$ because if you multiply numbers with exponents you add the exponents.

Now we've got $\frac{64a^6}{8a^2}=8a^4$ .

Sadly it has to be in exponential form. You can substitute $a$ into the equation if you know a.

3 0

3 years ago

3x+30+x=10+2x+5x+2 i need help fast

kupik [55]

Answer:

x=6

Step-by-step explanation:

Group Like Terms:

3x+x+30=10+2x+5x+2

Add similar elements 3x+x=4x:

4x+30=10+2x+5x+2

Add similar elements 2x+5x=7x:

4x+30=10+7x+2

Group like terms:

4x+30=7x+10+2

Add the numbers 10+2=12:

4x+30=7x+12

Subtract 30 from both sides:

4x+30-30=7x+12-30

Simplify:

4x=7x-18

Subtract 7x from both sides:

4x-7x=7x-18-7x

Simplify:

-3x=-18

Divide both sides by -3:

$\frac{-3x}{-3} =\frac{-18}{-3}$

Simplify:

x=6

Hence, the correct answer is 6

4 0

2 years ago

Help me with this plz

patriot [66]

Answer:

zero

Step-by-step explanation:

3 0

3 years ago

A healthcare provider monitors the number of CAT scans performed each month in each of its clinics. The most recent year of data

Rasek [7]

Answer: a. 1.981 < μ < 2.18

b. Yes.

Step-by-step explanation:

A. For this sample, we will use t-distribution because we're estimating the standard deviation, i.e., we are calculating the standard deviation, and the sample is small, n = 12.

First, we calculate mean of the sample:

$\overline{x}=\frac{\Sigma x}{n}$

$\overline{x}=\frac{2.31=2.09+...+1.97+2.02}{12}$

$\overline{x}=$ 2.08

Now, we estimate standard deviation:

$s=\sqrt{\frac{\Sigma (x-\overline{x})^{2}}{n-1} }$

$s=\sqrt{\frac{(2.31-2.08)^{2}+...+(2.02-2.08)^{2}}{11} }$

s = 0.1564

For t-score, we need to determine degree of freedom and $\frac{\alpha}{2}$ :

df = 12 - 1

df = 11

$\alpha$ = 1 - 0.95

α = 0.05

$\frac{\alpha}{2}=$ 0.025

Then, t-score is

$t_{11,0.025}$ = 2.201

The interval will be

$\overline{x}$ ± $t.\frac{s}{\sqrt{n} }$

2.08 ± $2.201\frac{0.1564}{\sqrt{12} }$

2.08 ± 0.099

The 95% two-sided CI on the mean is 1.981 < μ < 2.18.

B. We are 95% confident that the true population mean for this clinic is between 1.981 and 2.18. Since the mean number performed by all clinics has been 1.95, and this mean is less than the interval, there is evidence that this particular clinic performs more scans than the overall system average.

8 0

3 years ago