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Firlakuza [10]
4 years ago
11

the relationship between altitude and the boiling point is linear.AT an altitude of  8300ft 8300 ft , the liquid 

boils at  194.23 194.23 degrees Fahrenheit an altitude of  4200 ft , 4200 ft , the liqiud boils at  202.02 202.02 degrees fahrenheit.Write an equation giving the boiling point  b b of the liquid,in degrees fahrenheit in terms of altitude a in  feet . feet . What is the boiling point of the liqud at  2600 ft 2600 ft
Mathematics
1 answer:
mojhsa [17]4 years ago
5 0

Complete Question

The  relationship  between  altitude  and  the  boiling  point  is  linear. At  an  altitude  of   8300ft, the  liquid  boils  at   194.23 °  F

At  an  altitude  of   4200 ft ,  the  liquid  boils  at   202.02° F.

Write  an  equation  giving  the  boiling  point   b  of  the  liquid,  in  terms  of  altitude  a  in   feet . feet . What  is  the  boiling  point  of  the  liquid  at   2600ft

Answer:

The equation is  y  =  -0.001943x + 210.3569

At  2600ft  the temperature is  y  =  205.3051 \  °F

Step-by-step explanation:

From the question we are told that

    The temperature at 8300ft is 194.23 °  F

    The  temperature at 4200 ft is 202.02° F

Generally the slope for this relationship is mathematically represented as

      m  =  \frac{ 202.2 - 194.23}{ 4200 - 8300}

=>     m  = 0.001943  ^o  F / ft  

Generally the according to the point slope formula is

      y - y_1  =  m(x -x_1 )

=>   y - 194.23 =  -0.001943 (x - 8300 )

=>  y - 194.23 =  -0.001943x + 16.1269

=>  y  =  -0.001943x + 210.3569

Now we are given from the question that   x =  2600 ft

Then  

         y  =  -0.001943(2600) + 210.3569

=>      y  =  205.3051 \  °F

   

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Step-by-step explanation:

1. We want to know if matrix A is the inverse of matrix B, this means that if you do the product between B and A you have to obtain the identity matrix.

We have:

A=\left[\begin{array}{cc}4&-2\\-1&3\end{array}\right]

and

B=\left[\begin{array}{cc}3&2\\1&4\end{array}\right]

A and B are 2×2 matrices (2 rows and 2 columns), if you multiply them you have to obtain a 2×2 matrix.

Then if A is the inverse of B:

B.A=I

Where,

I=\left[\begin{array}{cc}1&0\\0&1\end{array}\right]

Observation:

If you have two matrices:

A=\left[\begin{array}{cc}a&b\\c&d\end{array}\right]\\and\\B=\left[\begin{array}{cc}e&f\\g&h\end{array}\right]\\\\\\A.B=\left[\begin{array}{cc}(a.e+b.g)&(a.f+b.h)\\(c.e+d.g)&(c.f+d.h)\end{array}\right]

Now:

B.A=\left[\begin{array}{cc}3&2\\1&4\end{array}\right].\left[\begin{array}{cc}4&-2\\-1&3\end{array}\right]\\\\\\B.A=\left[\begin{array}{cc}4.3+(-2).1&4.2+(-2).4\\(-1).3+3.1&(-1).2+3.4\end{array}\right]\\\\\\B.A=\left[\begin{array}{cc}12-2&8-8\\-3+3&-2+12\end{array}\right]\\\\\\B.A=\left[\begin{array}{cc}10&0\\0&10\end{array}\right]

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