Question

X^2-6x-25=0. Solve by completing the square.

Answer 1

Hey there,
x^2 -6x+25=0
Per quadratic formula, roots of ax^2+bx+c are
x=[-b+sqrt(b^2-4ac)]/2a and x=[-b-sqrt(b^2-4ac)]/2a

In this example, a=1, b=-6, and c=25
So, x= [6+sqrt(36-100)]/2 and x= [6-sqrt(36-100)]/2
=> x = [6+sqrt(-64)]/2 and x = [6-sqrt(-64)]/2 
=> x = 3+4i and x= 3-4i

Hope this helped you alot!!!!!!!!