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Katen [24]
3 years ago
11

22. 38.56 + 8 + 99.41 = 86.68

Mathematics
1 answer:
Andru [333]3 years ago
6 0

0.1

44

43

4

3432

27

87

34

23.9

05

345

234.70

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Q ÷ 2 -qp ÷ 6; let p = -6 and q = 10
ozzi

Answer:

15

Step-by-step explanation:

1. Plug in the values.

q=10

p=-6

10÷2-(10)(-6)÷6

2. Use PEMDAS.

10÷2+60÷6

5+10

15

5 0
3 years ago
If a student is chosen at random what is the probability they scored a 4 or 5
DaniilM [7]

Answer:

4= 40.0    5=10.0 chance

5 0
3 years ago
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A line passes through (−1, 7) and (2, 10). which answer is the equation of the line?
mart [117]
First you need to find the slope of the line. So what you need to do is y^2-y^1 / x^2-x^1

(x^1, y^1) (x^2, y^2)
( -1, 7) ( 2, 10)

10-7/ 2- (-1)
3/3=1
slope is 1

I got 8 as the y intercept. Reason how is that I made a table. And what I did was go back instead of going forward.

x y
-1 7
0 8
1 9
2 10

The answer would be x= 1 y= x + 8 y=8 But the answer choice you listed for A. would not match up the 2 coordinate you gave. Make sure a. should be x= 1 y= x + 8 y=8, not -x y= 8-x y=8
6 0
3 years ago
Which of the following statements is true?
Hitman42 [59]
If my memory serves me well, the only wtatement which is true is the last one: <span>D) All linear equation and all quadratic equations are polynomial equations.</span>
8 0
3 years ago
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Drag the tiles to the boxes to form correct pairs. Not all tiles will be used. Match the pairs of polynomials to their products.
andreyandreev [35.5K]

The products of the polynomials are:

  • (xy + 9y + 2) * (xy - 3) = x²y² - xy + 9xy² - 27y - 6
  • (2xy + x + y) * (3xy² - y) = 6x²y³ - 2xy² + 3x²y² -xy + 3xy³- y²
  • (x - y) * (x + 3y) = x² + 2xy + 3y²
  • (xy + 3x + 2) * (xy – 9)  = x²y² - 7xy + 3x²y - 27x  - 18
  • (x² + 3xy - 2) * (xy + 3)  = x³y + 3x² + 3x²y² + 7xy - 6
  • (x + 3y) * (x – 3y) = x² - 9y²

<h3>How to evaluate the products?</h3>

To do this, we multiply each pair of polynomial as follows:

<u>Pair 1: (xy + 9y + 2) and (xy – 3)</u>

(xy + 9y + 2) * (xy - 3)

Expand

(xy + 9y + 2) * (xy - 3) = x²y² - 3xy + 9xy² - 27y + 2xy - 6

Evaluate the like terms

(xy + 9y + 2) * (xy - 3) = x²y² - xy + 9xy² - 27y - 6

<u>Pair 2: (2xy + x + y) and (3xy² - y)</u>

(2xy + x + y) * (3xy² - y)

Expand

(2xy + x + y) * (3xy² - y) = 6x²y³ - 2xy² + 3x²y² -xy + 3xy³- y²

<u>Pair 3: (x – y) and (x + 3y) </u>

(x - y) * (x + 3y)

Expand

(x - y) * (x + 3y) = x² + 3xy - yx + 3y²

Evaluate the like terms

(x - y) * (x + 3y) = x² + 2xy + 3y²

<u>Pair 4: (xy + 3x + 2) and (xy – 9) </u>

(xy + 3x + 2) * (xy – 9)

Expand

(xy + 3x + 2) * (xy – 9)  = x²y² - 9xy + 3x²y - 27x + 2xy - 18

Evaluate the like terms

(xy + 3x + 2) * (xy – 9)  = x²y² - 7xy + 3x²y - 27x  - 18

<u>Pair 5: (x² + 3xy - 2) and (xy + 3) </u>

(x² + 3xy - 2) * (xy + 3)

Expand

(x² + 3xy - 2) * (xy + 3)  = x³y + 3x² + 3x²y² + 9xy - 2xy - 6

Evaluate the like terms

(x² + 3xy - 2) * (xy + 3)  = x³y + 3x² + 3x²y² + 7xy - 6

<u>Pair 6: (x + 3y) and (x – 3y)</u>

(x + 3y) * (x – 3y)

Apply the difference of two squares

(x + 3y) * (x – 3y) = x² - 9y²

Read more about polynomials at:

brainly.com/question/4142886

#SPJ1

5 0
2 years ago
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