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3 years ago

Factor completely. 2x^4 + 4x^3 - 30x^2 =

Mathematics

2 answers:

Aleksandr [31]3 years ago

8 0

Answer:

2x^2(x + 5)(x - 3).

Step-by-step explanation:

The Greatest Common Factor is 2x^2, so:

2x^4 + 4x^3 - 30x^2

= 2x^2(x^2 + 2x - 15) Now we factor the quadratic in the parentheses:

= 2x^2(x + 5)(x - 3).

den301095 [7]3 years ago

6 0

Answer:

$2x^2(x-3)(x+5)$

Step-by-step explanation:

The first thing that you can do is to factor out an x^2 from the expression.

x^2(2x^2+4x-30)

The next step is to factor out a 2.

2x^2(x^2+2x-15)

Finally, you can factor the quadratic inside.

2x^2(x-3)(x+5)

And now you're finished! Hope this helps!

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A car is traveling at a constant velocity. After two hours the car has traveled 110 miles. After four hours the car has traveled

Aleks04 [339]

I will take110+110 which will give me220

8 0

3 years ago

F(x)=2x^2-3x+7 evaluate f(-2)

Vilka [71]

Answer:

Step-by-step explanation:

Find two linear functions p(x) and q(x) such that (p (f(q(x)))) (x) = x^2 for any x is a member of R?

Let p(x)=kpx+dp and q(x)=kqx+dq than

f(q(x))=−2(kqx+dq)2+3(kqx+dq)−7=−2(kqx)2−4kqx−2d2q+3kqx+3dq−7=−2(kqx)2−kqx−2d2q+3dq−7

p(f(q(x))=−2kp(kqx)2−kpkqx−2kpd2p+3kpdq−7

(p(f(q(x)))(x)=−2kpk2qx3−kpkqx2−x(2kpd2p−3kpdq+7)

So you want:

−2kpk2q=0

and

kpkq=−1

and

2kpd2p−3kpdq+7=0

Now I amfraid this doesn’t work as −2kpk2q=0 that either kp or kq is zero but than their product can’t be anything but 0 not −1 .

Answer: there are no such linear functions.

6 0

2 years ago

Graph the function. Describe its position relative to the graph of the indicated function

sweet [91]

Answer:

Step-by-step explanation:

If the parent function is function $y=f(x)$ and $a>0,$ then

the graph of the function $y=f(x-a)$ is translated a units to the right graph of the parent function;
the graph of the function $y=f(x+a)$ is translated a units to the left graph of the parent function;
the graph of the function $y=f(x)+a$ is translated a units up graph of the parent function;
the graph of the function $y=f(x)-a$ is translated a units down graph of the parent function.