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MatroZZZ [7]
3 years ago
13

Which equations are related equations to x + 8 = 22?

Mathematics
2 answers:
andre [41]3 years ago
8 0

Answer:

x=22+8 and x+22=8nd 8=22_x

ohaa [14]3 years ago
4 0
The anwser should be D
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Find the scale factor of the dilation. Then tell whether it is enlargement or reduction.​
mariarad [96]

Answer:

  a) 1/2; reduction

  b) 5/4; enlargement

Step-by-step explanation:

In each case, the scale factor is CP'/CP. When it is more than 1, the dilation is an enlargement.

Even before you run the numbers, you can tell if it is an enlargement or not. If the dilated figure is larger, P is closer to C than is P'. If P' is closer to C, then it is a reduction.

a) CP'/CP = (4-2)/4 = 2/4 = 1/2 . . . . a reduction

__

b) CP'/CP = 25/20 = 5/4 . . . . an enlargement

4 0
3 years ago
J is the midpoint of hk. what is hj, jk, and hk
Lyrx [107]
Hj and jk are the same length line segments ( because the midpoint divides a line into two equal parts)
So hj = jk.

hk is the line segment which has the mid point j. It is the double of hj or jk. It can be the sum of hj and jk. 
hj + jk = hk 
      or
2 * hj = hk
      or 
2 * jk = hk
4 0
3 years ago
Read 2 more answers
What is the simplified form of V 100x35 ?
ElenaW [278]

Answer:

answer is 3500.

answer is 3500

answer is 3500

7 0
3 years ago
Integrate ​G(x,y,z)equalsz over the parabolic cylinder yequalszsquared​, 0less than or equalsxless than or equals2​, 0less than
yKpoI14uk [10]

I gather you're supposed to compute the integral of G(x,y,z)=z over a surface S that is the part of the parabolic cylinder y=z^2 with 0\le x\le2 and 0\le z\le\frac{\sqrt{15}}2.

We can parameterize S by

\vec s(x,z)=x\,\vec\imath+z^2\,\vec\jmath+z\,\vec k

with the given constraints on x and z. Take the normal vector to S to be

\vec s_x\times\vec s_z=-\vec\jmath+2z\,\vec k

so that the surface element is

\mathrm dS=\|\vec s_x\times\vec s_z\|\,\mathrm dx\,\mathrm dz=\sqrt{1+4z^2}\,\mathrm dx\,\mathrm dz

Then in the integral, we have

\displaystyle\iint_Sz\,\mathrm dS=\int_0^2\int_0^{\sqrt{15}/2}z\sqrt{1+4z^2}\,\mathrm dz\,\mathrm dx=\boxed{\frac{21}2}

5 0
3 years ago
Ok help me please guys ..what is 61=3b+7 ?
Neporo4naja [7]
61 = 3b + 7

3b + 7 = 61

3b = 61 - 7

3b = 54

b = 54/3

b = 18.
7 0
3 years ago
Read 2 more answers
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