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Zolol [24]
3 years ago
13

Choose the function whose graph is given below.

Mathematics
2 answers:
Alex17521 [72]3 years ago
7 0

Answer:

D. y = cot x

Step-by-step explanation:


Paladinen [302]3 years ago
6 0

Answer:

The correct answer is D) cot(x)

Step-by-step explanation:

We can tell this by the placement of the asymptotes. Each of them (0, pi 2pi, etc) are all at points where tan(x) = 0. As a result, we know that these would not exist on the graph of cot(x) since it is the inverse of tan(x)

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Andre45 [30]

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A prime number is a natural number greater than 1 that cannot be formed by multiplying two smaller natural numbers.

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What’s the answer in neeeeeeeeed it………
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10x

Step-by-step explanation:

3 0
3 years ago
Can you figure out the formula
puteri [66]

If "a" and "b" are two values of x-coordinate, and "m" is the midpoint between them, it means the distance from one end to the midpoint is the same as the distance from the midpoint to the other end

... a-m = m-b

When we add m+b to this equation, we get

... a+b = 2m

Solving for m gives

... m = (a+b)/2

This applies to y-coordinates as well. So ...

... The midpoint between (x1, y1) and (x2, y2) is ((x1+x2)/2, (y1+y2)/2)

_____

Jennifer had (x1, y1) = (-4, 10) and (x2, y2) = (-2, 6). So her calculation would be

... midpoint = ((-4-2)/2, (10+6)/2) = (-6/2, 16/2) = (-3, 8)

Brandon had (x1, y1) = (9, -4) and (x2, y2) = (-12, 8). So his calculation would be

... midpoint = ((9-12)/2, (-4+8)/2) = (-3/2, 4/2) = (-1.5, 2)

4 0
3 years ago
A parabola can be drawn given a focus of (-5, -4)(−5,−4) and a directrix of y=-6y=−6. Write the equation of the parabola in any
lord [1]

Answer:

\displaystyle \large{y=\dfrac{x^2}{4} + \dfrac{5x}{2} + \dfrac{5}{4}}

Step-by-step explanation:

Given:

  • Focus = (-5,-4)
  • Directrix = -6

To find:

  • Parabola Equation

Locus of Parabola (Upward/Downward)

\displaystyle \large{\sqrt{(x-a)^2+(y-b)^2} = |y-c|}

Where:

  • (a,b) = focus
  • c = directrix

Hence:

\displaystyle \large{\sqrt{(x+5)^2+(y+4)^2}=|y+6|}

Cancel square root by squaring both sides as we get:

\displaystyle \large{(x+5)^2+(y+4)^2=(y+6)^2}

Solve for y-term:

\displaystyle \large{(x+5)^2=(y+6)^2-(y+4)^2}\\\displaystyle \large{x^2+10x+25=y^2+12y+36-y^2-8y-16}\\\displaystyle \large{x^2+10x+25=4y+20}\\\displaystyle \large{x^2+10x+5=4y}\\\displaystyle \large{y=\dfrac{x^2}{4} + \dfrac{5x}{2} + \dfrac{5}{4}}

4 0
2 years ago
What is 4+4? pls help
Nataly_w [17]

Answer:

8

Step-by-step explanation:

add 4 plus 4 then omg watch this you get 8 abracadabra....

you're welcome

3 0
3 years ago
Read 2 more answers
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