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2 years ago

I got it wrong and I am doing test corrections. Does anyone know the answer? If you do please reply asap thanks!!

Mathematics

2 answers:

LUCKY_DIMON [66]2 years ago

8 0

Maybe 8 by 14 hope this helps

iren2701 [21]2 years ago

8 0

12/18=4/x cross multiply. 18*4=72 72/12=6 so the picture would be 6 inches tall

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During a musical an orchestra is playing. As the music plays, the volume changes in the beginning of the piece can be modeled by

noname [10]

Answer:

Kindly check explanation

Step-by-step explanation:

Given the model:

s = 10│x - 4│+ 50

s represents the sound level in decibels and x represents the number of measures of music played

To find x at s = 80

The equation becomes /

80 = 10│x - 4│+ 50

Subtract 50 from both sides of the equation

80 - 50 = 10 |x - 4| + 50 - 50

30 = 10 | x - 4 |

Divide both sides by 10

30/10 = 10|x - 4| / 10

3 = |x - 4|

|x - 4| is an absolute value expression

±3 = |x - 4|

x = 3 + 4 = 7

x = - 3 + 4 = 1

4 0

3 years ago

A car maintains a speed of 23 mi/h for 5 seconds. It then accelerates to a speed of 46 mi/h in 5 seconds. It maintains that spee

Vika [28.1K]

The answer is a because it starts at 0 then goes up to 23 and then it goes up to 46.

6 0

2 years ago

Read 2 more answers

Find the greatest common factor 32a^3b^2, 44ab^3 and 40a^2b

Ronch [10]

$\32a^3b^2 \ , \ 44ab^3 \ , \ 40a^2b\\
$

$\text {Taking out common factor : } \\ \\
4ab(8a^2b) + 4ab(11b^2) + 4ab(10a)$

$\text { greatest common factor = } 4ab$

3 0

3 years ago

2.The number of tickets sold to a play for each showing is 78, 84, 87, 80, 91, 95, and 80.

Luden [163]

Answer:

$Min =78$

The maximum is :

$Max = 95$

Now we can calculate the median since the sample size os n =7 the median would be the middle value at the position 4 from the dataset ordered and we got:

$Median =84$

Now we can find the quartile 1 we analyze the first 4 values 78, 80,80, 84 and the first quartile would be:

$Q_1= \frac{80+80}{2}= 80$

Now we can find the quartile 3 we analyze the last 4 values 84,87, 91, 95 and the third quartile would be:

$Q_3= \frac{87+91}{2}=89$

And finally the 5 number summary would be:

$Min = 78, Q_1 = 80, Median=84, Q_3 = 89, Max=96$

Step-by-step explanation:

We have the following data given:

78, 84, 87, 80, 91, 95, and 80.

The first step is order the dataset on increasing way and we got:

78, 80,80, 84,87, 91, 95

We can begin finding the minimum value and for this case is:

$Min =78$

The maximum is :

$Max = 95$

Now we can calculate the median since the sample size os n =7 the median would be the middle value at the position 4 from the dataset ordered and we got:

$Median =84$

Now we can find the quartile 1 we analyze the first 4 values 78, 80,80, 84 and the first quartile would be:

$Q_1= \frac{80+80}{2}= 80$

Now we can find the quartile 3 we analyze the last 4 values 84,87, 91, 95 and the third quartile would be:

$Q_3= \frac{87+91}{2}=89$

And finally the 5 number summary would be:

$Min = 78, Q_1 = 80, Median=84, Q_3 = 89, Max=96$

5 0

3 years ago

How to determine if a function is even or odd calculus?

aalyn [17]

A function $f(x)$ is even if $f(-x)=f(x)$ , and is odd if $f(-x)=-f(x)$ .

Example:

$f(x)=x^2$ is even, since $f(-x)=(-x)^2=x^2=f(x)$ .

$g(x)=x^3-x$ is odd, since $g(-x)=(-x)^3-(-x)=-x^3+x=-(x^3-x)=-g(x)$ .

6 0

2 years ago