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IRISSAK [1]
3 years ago
7

I got it wrong and I am doing test corrections. Does anyone know the answer? If you do please reply asap thanks!!

Mathematics
2 answers:
LUCKY_DIMON [66]3 years ago
8 0
Maybe 8 by 14 hope this helps
iren2701 [21]3 years ago
8 0
12/18=4/x cross multiply. 18*4=72 72/12=6 so the picture would be 6 inches tall
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The difference of 5 times the cube of x cubed and<br> the quotient of 4 times x and 3
Anvisha [2.4K]

Answer:

I don't know what you are looking for, but I am going with (15x^3 - 4x)/3

Step-by-step explanation:

5x^3 - 4x/3

5x^3/1 - 4x/3

15x^3/3 - 4x/3

(15x^3 - 4x)/3

3 0
3 years ago
the school that imani goes to is selling tickets to a spring musical. on the first day of ticket sales the school sold 8 adult t
9966 [12]
If we let x and y represent the prices of adult and child tickets, respectively, then we can write two equations based on the daily sales.
  8x +5y = 108
  x +14y = 67

A graphing calculator shows the solution of these equations to be
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3 0
3 years ago
1. The following statement is false. Highlight the two words that should be
mafiozo [28]

Answer:

highlight input and output.

Step-by-step explanation:

sorry if this doesn't work. i'm not 100% sure but its worth a try.

4 0
3 years ago
Find the standard form of the equation of the hyperbola satisfying the given conditions: X intercept +/- 6; foci at (-10,0) and
uysha [10]

Answer:

\frac{x^{2}}{36} - \frac{y^{2}}{64}=1

Step-by-step explanation:

Given an hyperbola with the following conditions:

  • Foci at (-10,0) and (10,0)
  • x-intercept +/- 6;

The following holds:

  • The center is midway between the foci, so the center must be at (h, k) = (0, 0).
  • The foci are 10 units to either side of the center, so c = 10 and c^2 = 100
  • The center lies on the origin, so the two x-intercepts must then also be the hyperbola's vertices.

Since the intercepts are 6 units to either side of the center, then a = 6 and a^2 = 36.

Then, a^2+b^2=c^2\\b^2=100-36=64

Therefore, substituting a^2 = 36. and b^2=64 into the standard form

\frac{x^{2}}{a^2} - \frac{y^{2}}{b^2}=1\\We \: have:\\ \dfrac{x^{2}}{36} - \dfrac{y^{2}}{64}=1

4 0
3 years ago
HURRY HELP QUICK
LuckyWell [14K]

Answer:

m is greater than or equal to -1, m is less than or equal to -10

Step-by-step explanation:

-1+-10

6 0
2 years ago
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