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makvit [3.9K]
3 years ago
9

6. which solid did the net form

Mathematics
1 answer:
In-s [12.5K]3 years ago
5 0

Answer:

Hexagonal Pyramid

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Please help with these two equations it’s a math test!!
wolverine [178]

Answer:

The measure of angle 8 is 50 degrees and the measure of angle 7 is 45 degrees

Step-by-step explanation:

4 0
3 years ago
77 is 22.3% of what number
Elza [17]

Answer:

345.29

Step-by-step explanation:

77 divided by .223 = 345.2914798

6 0
3 years ago
The formula c = 5p + 215 relates c, the total cost in dollars of hosting a birthday party at a skating rink, to p, the number of
yarga [219]
Given:
c = cost
p = people
Spent $300

Formula: c=5p+215

Solving for how many people (p)

C=5P+215
(300)=5P+215               (Subtract 215 on both sides)
85=5P                           (Divide by 5 on both sides)
17=P

The answer is 17. 17 people can afford to host a birthday party.
3 0
3 years ago
Sally Sue had spent all day preparing for the prom. All the glitz and the glamour of the evening fell apart as she stepped out o
Nuetrik [128]

We have the function

p(t)=550(1-e^{-0.039t})

Therefore we want to determine when we have

p(t_0)=550

It means that the term

e^{-0.039t}

Must go to zero, then let's forget the rest of the function for a sec and focus only on this term

e^{-0.039t}\rightarrow0

But for which value of t? When we have a decreasing exponential, it's interesting to input values that are multiples of the exponential coefficient, if we have 0.039 in the exponential, let's define that

\alpha=\frac{1}{0.039}

The inverse of the number, but why do that? look what happens when we do t = α

e^{-0.039t}\Rightarrow e^{-0.039\alpha}\Rightarrow e^{-1}=\frac{1}{e}

And when t = 2α

e^{-0.039t}\Rightarrow e^{-0.039\cdot2\alpha}\Rightarrow e^{-2}=\frac{1}{e^2}

We can write it in terms of e only.

And we can find for which value of α we have a small value that satisfies

e^{-0.039t}\approx0

Only using powers of e

Let's write some inverse powers of e:

\begin{gathered} \frac{1}{e}=0.368 \\  \\ \frac{1}{e^2}=0.135 \\  \\ \frac{1}{e^3}=0.05 \\  \\ \frac{1}{e^4}=0.02 \\  \\ \frac{1}{e^5}=0.006 \end{gathered}

See that at t = 5α we have a small value already, then if we input p(5α) we can get

\begin{gathered} p(5\alpha)=550(1-e^{-0.039\cdot5\alpha}) \\  \\ p(5\alpha)=550(1-0.006) \\  \\ p(5\alpha)=550(1-0.006) \\  \\ p(5\alpha)=550\cdot0.994 \\  \\ p(5\alpha)\approx547 \end{gathered}

That's already very close to 550, if we want a better approximation we can use t = 8α, which will result in 549.81, which is basically 550.

Therefore, we can use t = 5α and say that 3 people are not important for our case, and say that it's basically 550, or use t = 8α and get a very close value.

In both cases, the decimal answers would be

\begin{gathered} 5\alpha=\frac{5}{0.039}=128.2\text{ minutes (good approx)} \\  \\ 8\alpha=\frac{8}{0.039}=205.13\text{ minutes (even better approx)} \end{gathered}

7 0
1 year ago
A group of people were asked if they had run a red light in the last year. 456 responded "yes", and 304 responded "no". Find the
Amiraneli [1.4K]

Answer:

The probability that if a person is chosen at random has run to red light in the last year is 60%.

Step-by-step explanation:

Since a group of people were asked if they had run a red light in the last year, and 456 responded "yes", and 304 responded "no", to find the probability that if a person is chosen at random, they have run a red light in the last year, the following calculation must be performed:

456 + 304 = 760

760 = 100

456 = X

456 x 100/760 = X

45600/760 = X

60 = X

Therefore, the probability that if a person is chosen at random has run to red light in the last year is 60%.

4 0
3 years ago
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