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Pavel [41]
3 years ago
12

A group of people were asked if they had run a red light in the last year. 456 responded "yes", and 304 responded "no". Find the

probability that if a person is chosen at random, they have run a red light in the last year.
Mathematics
1 answer:
Amiraneli [1.4K]3 years ago
4 0

Answer:

The probability that if a person is chosen at random has run to red light in the last year is 60%.

Step-by-step explanation:

Since a group of people were asked if they had run a red light in the last year, and 456 responded "yes", and 304 responded "no", to find the probability that if a person is chosen at random, they have run a red light in the last year, the following calculation must be performed:

456 + 304 = 760

760 = 100

456 = X

456 x 100/760 = X

45600/760 = X

60 = X

Therefore, the probability that if a person is chosen at random has run to red light in the last year is 60%.

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5 0
3 years ago
The test to detect the presence of respiratory syncytial virus is 97% accurate for a person who has the virus and 99% accurate f
Setler79 [48]

Answer:

The probability that a randomly selected person gets incorrect result is 2.2 × 10⁻⁴

Step-by-step explanation:

The parameters given are;

The accuracy of the test for a person who has the respiratory synctial virus = 97%

The accuracy of the test for a person who does not have the respiratory synctial virus = 99%

We have;

a = TP =

b = FP

c = FN

d = TN

a/(a + c) = 0.97

d/(d + b) = 0.99

a/(a + b) = 0.97*0.0055/(0.97*0.0055 + (1 - 0.99)*(1-0.0055))

PPV = 0.349 = 34.9%

Therefore, we have;

a/(a + c) = 0.97 and

a/(a + b)  =  0.349

0.97(a + c) =0.349(a + b)

(0.97 - 0.349)a = 0.349·b - 0.97·c

a = (0.349·b - 0.97·c)0.621

b × (1 - 0.0055) = (1 - 0.97)×(1 - 0.0055)

b = 1 - 0.97 = 0.03

Similarly,

c = 1 - 0.99 = 0.01

The proportion of the population that have false positive and false negative = 0.03 + 0.01 = 0.04 = 4%

The probability that a randomly selected person gets incorrect result = 0.04×0.0055 = 0.00022.

5 0
3 years ago
A survey of a group of students was conducted. The students were asked if they were taking a
sertanlavr [38]
<h3>Answer:  32</h3>

Explanation:

We add up the numbers found in the "math" circle

9+7+11+5 = 32

5 0
2 years ago
X² + y² = 34<br>x + y =8​
Nataly [62]

Step-by-step explanation:

{x}^{2}  +  {y}^{2}  = 34 \\ x + y = 8 \\ x = 8 - y \\ substitute \: x \: in \\  {x}^{2}  +  {y}^{2}  = 34 \\  {(8 - 4)}^{2}  +  {y}^{2}  = 34 \\  {(8 - 4) }^{2}  =  {y}^{2}  - 16y + 64 \\   {y}^{2}  - 16y + 64 +  {y}^{2}  = 34 \\  {2y}^{2}  - 16y + 64 = 34 \\ {2y}^{2}  - 16y + 64  - 34 = 0 \\  {2y}^{2}  - 16y + 30 = 0 \\ 2 {y}^{2}  - 6y - 10y + 30 = 0 \\ (2 {y}^{2}  - 6y) - (10y + 30) = 0 \\ 2y(y - 3) - 10(y - 3) = 0 \\ (2y - 10)(y - 3) \\ 2y = 10 \\ y  = \frac{10}{2}  \\ y = 5 \\ or \\ y = 3 \\ if \: y = 5 \:  \: x = 3 \\ if \: y = 3 \:  \:  x = 5

4 0
3 years ago
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