The proof is given below. Please go through it.
Step-by-step explanation:
To solve Δ ABC ≅ Δ DBC
From Δ ABC and Δ DBC
AB = BD (given)
AC = CD (given)
BC is common side
By SSS condition Δ ABC ≅ Δ DBC ( proved)
To solve Δ EHF ≅ Δ GHF
Δ EHF and Δ GHF
EH = HG ( given)
∠ EFH = ∠ GFH ( each angle is 90°)
HF is common side
By RHS condition
Δ EHF ≅ Δ GHF
60
D>0, there are 2 distinct real roots
Explanation:
3x2+6x−2=0
a=3,b=6,c=−2
The formula for discriminant is b2−4acSubstitute the given values.
b2−4ac
(6)2−4(3)(−2)
=60
therefore, D>0, there are 2 distinct real roots
Answer:
The more time spent reading
Step-by-step explanation:
The 2 that had 4 hours of read time had an A
You put all the numbers on one side of the equation and letters on another.
0.25r + 0.5r - r = 0.5 +0.125
-0.75r = 0.625 divide both sides by -0.75
r = -0.125
Answer:
The answer is A
Step-by-step explanation:
